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Anon25 [30]
3 years ago
8

A 0.0780 kg lemming runs off a 5.36 m high cliff at 4.84 m/s. what is its potential energy (PE) when it is 2.00 m above the grou

nd PLEASE HELP
Physics
1 answer:
vagabundo [1.1K]3 years ago
3 0

The potential energy at 2.00 m above the ground is 1.53 J

Explanation:

The gravitational potential energy of an object is given by

U=mgh

where

m is the mass of the object

g is the acceleration of gravity

h is the height of the object above the ground

In the problem, we have:

m = 0.0780 kg is the mass of the lemming

g=9.8 m/s^2 is the acceleration of gravity

h = 2.00 m is the height

Substituting, we find its potential energy at 2.00 m above the ground:

U=(0.0780)(9.8)(2.00)=1.53 J

Learn more about potential energy here:

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

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Rick shoots a basketball at an angle of 35' from the horizontal. It leaves his hands 7 feet from the ground with a velocity of 2
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Given:

The angle of projection of the basketball, θ=35°

The height at which the ball leaves the hand, h=7 ft

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To find:

The parametric equations describing the shot.

Explanation:

The range, x of the basketball is given by,

x=v\cos\theta t

On substituting the known values,

\begin{gathered} x=20\times\cos35\degree\times t \\ \implies x=16.4t \end{gathered}

The change in the height, y of the basketball is given by,

y=-v\sin\theta t+\frac{1}{2}gt^2

Where g is the acceleration due to gravity.

On substituting the known values,

\begin{gathered} y=-20\times\sin35\degree\times t+\frac{1}{2}\times32\times t^2 \\ \implies y=-11.5t+16t^2 \end{gathered}

Final answer:

The parametric equations describing the shot are

\begin{gathered} \begin{equation*} x=16.4t \end{equation*} \\ \begin{equation*} y=-11.5t+16t^2 \end{equation*} \end{gathered}

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