Answer:
The ratio of the diameter of iron to Cu is;
![\frac{d{Fe} }{ d{Cu} } =\sqrt{\frac{p_{Fe} }{ p_{Cu} }}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7BFe%7D%20%20%20%7D%7B%20d%7BCu%7D%20%20%20%7D%20%3D%5Csqrt%7B%5Cfrac%7Bp_%7BFe%7D%20%7D%7B%20p_%7BCu%7D%20%7D%7D)
Explanation:
R=(ρL)/A
- R is resistance,
- L is length,
- A is area,
- ρ is resistivity
- d is diameter
from the question the two materials have the same resistance per unit length.
![\frac{R}{L}= \frac{p}{A}](https://tex.z-dn.net/?f=%5Cfrac%7BR%7D%7BL%7D%3D%20%5Cfrac%7Bp%7D%7BA%7D)
for iron =
for copper
This means we can equate ρ/A for both materials.
![\frac{p_{Fe} }{A_{Fe} } =\frac{p_{Cu} }{A_{Cu} }](https://tex.z-dn.net/?f=%5Cfrac%7Bp_%7BFe%7D%20%7D%7BA_%7BFe%7D%20%7D%20%3D%5Cfrac%7Bp_%7BCu%7D%20%7D%7BA_%7BCu%7D%20%7D)
re-arranging the equation we have,
![\frac{A_{Fe}}{A_{Cu} } =\frac{p_{Fe} }{ p_{Cu} }](https://tex.z-dn.net/?f=%5Cfrac%7BA_%7BFe%7D%7D%7BA_%7BCu%7D%20%7D%20%3D%5Cfrac%7Bp_%7BFe%7D%20%7D%7B%20p_%7BCu%7D%20%7D)
![A=\pi \frac{d^{2} }{4}](https://tex.z-dn.net/?f=A%3D%5Cpi%20%5Cfrac%7Bd%5E%7B2%7D%20%7D%7B4%7D)
![\frac{A_{Fe}}{A_{Cu} } =\frac{d^{2}{Fe} }{ d^{2}{Cu} }](https://tex.z-dn.net/?f=%5Cfrac%7BA_%7BFe%7D%7D%7BA_%7BCu%7D%20%7D%20%3D%5Cfrac%7Bd%5E%7B2%7D%7BFe%7D%20%20%20%7D%7B%20d%5E%7B2%7D%7BCu%7D%20%20%20%7D)
![\frac{d^{2}{Fe} }{ d^{2}{Cu} } =\frac{p_{Fe} }{ p_{Cu} }](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5E%7B2%7D%7BFe%7D%20%20%20%7D%7B%20d%5E%7B2%7D%7BCu%7D%20%20%20%7D%20%3D%5Cfrac%7Bp_%7BFe%7D%20%7D%7B%20p_%7BCu%7D%20%7D)
![\frac{d{Fe} }{ d{Cu} } =\sqrt{\frac{p_{Fe} }{ p_{Cu} }}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7BFe%7D%20%20%20%7D%7B%20d%7BCu%7D%20%20%20%7D%20%3D%5Csqrt%7B%5Cfrac%7Bp_%7BFe%7D%20%7D%7B%20p_%7BCu%7D%20%7D%7D)
I am so sure it's 600,000 x 500 so you get 300,000,000
g Generally the accepted value of acceleration due to gravity is 9.801 ![m/s^2](https://tex.z-dn.net/?f=m%2Fs%5E2)
as per the question the acceleration due to gravity is found to be 9.42
in an experiment performed.
the difference between the ideal and observed value is 0.381.
hence the error is -![\frac{0.381}{9.801} *100](https://tex.z-dn.net/?f=%5Cfrac%7B0.381%7D%7B9.801%7D%20%2A100)
=3.88735 percent
the error is not so high,so it can be accepted.
now we have to know why this occurs-the equation of time period of the simple pendulum is give as-![T=2\pi\sqrt[2]{l/g}](https://tex.z-dn.net/?f=T%3D2%5Cpi%5Csqrt%5B2%5D%7Bl%2Fg%7D)
![g=4\pi^2\frac{l}{T^2}](https://tex.z-dn.net/?f=g%3D4%5Cpi%5E2%5Cfrac%7Bl%7D%7BT%5E2%7D)
As the experiment is done under air resistance,so it will affect to the time period.hence the time period will be more which in turn decreases the value of g.
if this experiment is done in a environment of zero air resistance,we will get the value of g which must be approximately equal to 9.801 ![m/s^2](https://tex.z-dn.net/?f=m%2Fs%5E2)
AWhich of the following would most likely cause a decrease in the quantity supplied? A decrease in price.