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makvit [3.9K]
3 years ago
6

A 200cc container holds a gas at a temperature of 60°C and 10000 Pa. What is the new temperature if volume changes to 100cc and

the new pressure is 45000
Pa?
Chemistry
1 answer:
creativ13 [48]3 years ago
3 0

Answer:

New temp = 135°C

Explanation:

From ideal gas equation

\frac{p1 \:  \times  \: v1}{t1}  =  \frac{p2 \:  \times  \: v2}{t2}  \\

But; P1 = 10000Pa. P2 = 45000

V1 = 200 cc. V2 = 100 cc

T1 = 60°C. T2 = ??

From our formulae above

\frac{10000 \times200 }{60}  =  \frac{45000 \times 100}{t2}then T2= 45000×100×60÷ (10000×200)

T2= 135°C

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