Ask question

Ask question

All categories

3 years ago

12

You are measuring the effects of salt on water's ability to freeze. To one of your water samples, you add sodium chloride (NaCl,

or salt). In this solution, which part is the solvent?
Question 8 options:

Water

NaCl

Both

Neither

1 answer:

yulyashka [42]3 years ago

7 0

Answer:

water

water is the worlds best solvent cause it can melt many different things also it is called the "Universal Solvent"

You might be interested in

What does this quote mean to you? <br> "You may need to fight a battle more then once to win."

Scilla [17]

Answer:

this means try your best until you succeed

Explanation:

7 0

3 years ago

Read 2 more answers

Atoms of which of the following elements have the smallest atomic radius?

Ad libitum [116K]

Answer:

The answer is helium, I hope this is helpful :)

7 0

3 years ago

That big lorry hit the new car.change to passive voice

Black_prince [1.1K]

I don’t understand the question? Maybe try rewording it?

8 0

3 years ago

You are starting with 2 pounds of 30% acetic acid solution. You want to dilute

Tpy6a [65]

Answer:

The mass of water to be added is 2 pounds

Explanation:

The given parameters are;

The mass of the given solution = 2 pounds

The concentration of the given solution = 30%

The desired concentration of the solution = 15%

The mass, m of the acetic acid in the given solution = 30% × 2 pounds

m = 30/100 × 2 pounds = 0.6 pounds

To make a 15% acetic acid solution of acetic acid, the mass X of the required volume, is given as follows;

15% of X = 0.6 pounds

15/100 × X = 3/20 × 0.6 pounds

∴ The mass of the solution required X = 0.6 × 20/3 = 4 pounds

The mass of the solution that will contain 0.6 pounds of acetic acid giving a 15% acetic acid solution is 4 pounds

Therefore, the mass of water to be added to the original solution to make the a 15% acetic acid solution is 2 pounds.

8 0

4 years ago

The heat of vaporization Δ1, of toluene (C6H5CH3) is 38.1 kJ/mol. Calculate the change in entropy AS when 207. g of toluene boil

AveGali [126]

Answer: The change in entropy change when 207 g of toluene boils at $110.6^{o}C$ is 223 $J/K$ .

Explanation:

It is given that mass of toulene is 207 g and its molar mass is 92.14 g/mol. So, its moles will be calculated as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{207 g}{92.14 g/mol}$

= 2.25 moles

As we are given that heat of vaporization for 1 mol is 38.1 kJ/mol. So, heat of vaporization for 2.25 moles will be calculated as follows.

$2.25 moles \times 38.1 KJ/mol$

= 85.725 KJ

Now, we know that the relation between enthalpy change and entropy change is as follows.

$\Delta S = \frac{\Delta H}{\Delta T}$

= $\frac{85.725 kJ}{(110.6 + 273) K}$

= 0.223 $kJ/K$

or, = 223 $J/K$ (as 1 kJ = 1000 J)

Thus, we can conclude that the change in entropy change when 207 g of toluene boils at $110.6^{o}C$ is 223 $J/K$ .

7 0

4 years ago