Answer = 330 m/s
The wave equation is as follows:
Wave speed = wavelength x frequency
The known values are:
Wavelength = 3m
Frequency = 110 Hz
Substitute the known values into the wave equation to find the wave speed.
Wave speed = 3 x 110
Wave speed = 330 m/s
Answer:
Explanation:
The region around a charged particle where another charged particle experiences a force of attraction or repulsion is called electric field.
The strength of electric field is defined as the force experienced by the unit positive test charge.
E = F / q
Electric field strength is a vector quantity and it is measured in newton per coulomb.
Where, F is the force of attraction or repulsion between the two charges and q is the test charge on which the electric field strength is to be calculated.
The strength of electric field is more if the field is strong. It means more be the electric field strength at a point more be the electric field.
Answer:
9.73 x 10⁻¹⁰ m
Explanation:
According to Heisenberg uncertainty principle
Uncertainty in position x uncertainty in momentum ≥ h / 4π
Δ X x Δp ≥ h / 4π
Δp = mΔV
ΔV = Uncertainty in velocity
= 2 x 10⁻⁶ x 3 / 100
= 6 x 10⁻⁸
mass m = 0.9 x 10⁻¹⁵ x 10⁻³ kg
m = 9 x 10⁻¹⁹
Δp = mΔV
= 9 x 10⁻¹⁹ x 6 x 10⁻⁸
= 54 x 10⁻²⁷
Δ X x Δp ≥ h / 4π
Δ X x 54 x 10⁻²⁷ ≥ h / 4π
Δ X = h / 4π x 1 / 54 x 10⁻²⁷
= ![\frac{6.6\times10^{-34}}{4\times3.14\times54\times10^{-27}}](https://tex.z-dn.net/?f=%5Cfrac%7B6.6%5Ctimes10%5E%7B-34%7D%7D%7B4%5Ctimes3.14%5Ctimes54%5Ctimes10%5E%7B-27%7D%7D)
= 9.73 x 10⁻¹⁰ m
Answer:
earth
Explanation:
The formula for the orbital period of the moon is given by
![T = 2\pi \sqrt{\frac{r}{g}}](https://tex.z-dn.net/?f=T%20%3D%202%5Cpi%20%5Csqrt%7B%5Cfrac%7Br%7D%7Bg%7D%7D)
As the time period is inversely proportional to the square root of the acceleration due to gravity of the planet.
As the value of acceleration due to gravity on Jupiter is more than the earth, so the period of moon around the earth is large as compared to the period of the moon around the Jupiter when the distance is same.