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dem82 [27]
3 years ago
5

Which actions are part of the process of scientific inquiry? Check all that apply

Chemistry
1 answer:
makkiz [27]3 years ago
7 0

Answer:

How are we supposed to answer that if there is nothing to see

Explanation:

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Razak uses 70 W fan and a 40 w lamp for eight hours a day, Calculate the amount of energy he used in a month. NORS Analysing​
Anastasy [175]

Answer:

70 W and 40 w

there are 28 days in a month

Add those 2 together and get 110

then mutlpy by 28

3,080 amount of energy

6 0
2 years ago
Zora wants to dissolve a solute in a solvent quickly. Which best describes what she should do?
lesya692 [45]

Answer:

C    shake it repeatedly

Explanation:

i think thats the answer if not sorry hope it helps you.

4 0
3 years ago
In your own words, describe what is the role or function of the neutron in the atom's nucleus
pochemuha

Neutrons are very important in provide stability for an atom. When atoms are created by fusion, neutrons are included in this process. Because protons don't like each other and repel each other that's where neutrons come in.

3 0
3 years ago
Read 2 more answers
Ammonia (NH3) is widely used as a fertilizer
ratelena [41]

Answer:

82.28g

Explanation:

Given parameters:

Number of moles of hydrogen gas = 7.26 moles

Unknown:

Amount of ammonia produced = ?

Solution:

We have to write the balanced equation first.

              N₂    +   3H₂    →    2NH₃

Now, we work from the known to the unknown;

   

                  3 moles of H₂ will produce 2 moles of NH₃

                7.26 mole of H₂ will produce \frac{7.26 x 2}{3}  = 4.84 moles of NH₃

Molar mass of NH₃ = 14 + 3(1) = 17g/mol

Mass of NH₃  = number of moles  x molar mass = 4.84 x 17 = 82.28g

3 0
3 years ago
A piston confines 0.200 mol Ne(g) in 1.20 at 25 degree C. Two experiments are performed. (a) The gas is allowed to expand throug
djyliett [7]

Answer:

The second experiment (reversible path) does more work

Explanation:

Step 1:

A piston confines 0.200 mol Ne(g) in 1.20L at 25 degree °C

<em>(a) The gas is allowed to expand through an additional 1.20 L against a constant of 1.00atm</em>

<em></em>

Irreversible path: w =-Pex*ΔV

⇒ with Pex = 1.00 atm

⇒ with ΔV = 1.20 L

W = -(1.00 atm) * 1.20 L

W = -1.20L*atm *101.325 J /1 L*atm = -121.59 J

<em>(b) The gas is allowed to expand reversibly and isothermally to the same final volume.</em>

<em></em>

W = -nRTln(Vfinal/Vinitial)

⇒ with n = the number of moles = 0.200

⇒ with R = gas constant = 8.3145 J/K*mol

⇒ with T = 298 Kelvin

⇒ with Vfinal/Vinitial  = 2.40/1.20 = 2

W = -(0.200mol) * 8.3145 J/K*mol *298K *ln(2.4/1.2)

W = -343.5 J

The second experiment (reversible path) does more work

7 0
3 years ago
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