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madreJ [45]
3 years ago
7

What mass of water would you need to have 15.0 miles of H2O

Chemistry
1 answer:
ss7ja [257]3 years ago
7 0

Answer: 270 g H2O

Explanation: solution attached

Use the relationship of 1 mole H2O is equal to its molar mass 18g H2O

15.0 moles H2O x 18g H2O / 1 mole H2O

= 270 g H2O

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Alpha and Beta particles can be stopped by our skin. Gamma particles cannot be stopped by our skin.
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1. If we have a reaction of Zn3PO4 and HCl, what would the products of this
Vladimir79 [104]

Answer:

1. The products of this reaction are ZnCl₂ and H₃PO₄.

2. 14.57 g.

Explanation:

<em>1. What would the products of this  reaction be?</em>

  • The balanced reaction between Zn₃(PO₄)₂ and HCl is represented as:

<em>Zn₃(PO₄)₂ + 6HCl → 3ZnCl₂ + 2H₃PO₄,</em>

It is clear that 1.0 mol of Zn₃(PO₄)₂ reacts with 6.0 mol of HCl to produce 3.0 mol of ZnCl₂ and 2.0 mol of H₃PO₄.

So, the products of this reaction are ZnCl₂ and H₃PO₄.

<em>2. If we produced 13.05 g of H₃PO₄, how many grams of  hydrochloric acid would be need to start with?​</em>

  • Firstly, we should get the no. of moles (n) of 13.05 grams of H₃PO₄:

n = mass/molar mass = (13.05 g)/(97.994 g/mol) = 0.1332 mol.

<u><em>Using cross-multiplication:</em></u>

6.0 mol of HCl needed to produce → 2.0 mol of H₃PO₄, from stichiometry.

??? mol of HCl needed to produce → 0.1332 mol of H₃PO₄.

∴ The no. of moles of HCl needed = (6.0 mol)(0.1332 mol)/(2.0 mol) = 0.3995 mol.

∴ The mass of HCl needed = n*molar mass = (0.3995 mol)(36.46 g/mol) = 14.57 g.

<em>So, the grams of  hydrochloric acid would be need to start with = 14.57 g.</em>

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4 years ago
If oxygen is removed from a sample of air as iron rust, what happens to the particle pressure of oxygen in the air?
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Answer : It increases

Rusting is where oxygen binds to iron and forms iron oxide.

So once iron rusts, there is oxygen, just not in air; it's in the iron oxide.


All reactions are reversible, albeit at different rates (the "irreversible" ones are still reversible, but much slower given that they take so much collision luck and energy.

5 0
3 years ago
Which element in Group 17 is the most active nonmetal? (1) Br (2) I (3) Cl (4) F
Maksim231197 [3]

The element of the group 17 that is most active non metal is fluorine.

The group 17 of the periodic table contains bromine(Br), iodine(I), Chlorine(Cl) and fluorine(F).

Among all the elements of the group 17. Fluorine is the smallest in size.

Because of the small size of fluorine it has the highest electronegativity in group 17.

This high electronegativity makes it a very active non metal. It provides a very high oxidizing power and low dissociation energy to the fluorine atom.

Also because of the very small size the source of attraction between the nucleus and the electrons is very high in floor in atom.

It reacts readily to form oxides and hydroxides.

So, we can conclude here that fluorine is the most active non metal of group 17.

To know more about group 17, visit,

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What is the name of the compound CO?
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Carbon monoxide (CO) is the name
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