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qaws [65]
3 years ago
6

Why does ionization energy decrease down a group?

Chemistry
1 answer:
german3 years ago
3 0
Ionization energy = the amount of energy it takes for an atom to lose an electron

Remember that the nucleus is positively charged and the electrons are negatively charged. Because those opposite charges attract, the nucleus is pulling the electron towards it and so, the closer an electron is to the nucleus of an atom, the stronger it is being pulled.

Now remember that as more electrons are added to match the number of protons, the shells fill up and each new shell that is made to accommodate for the electrons is further away from the nucleus. That means that the more electrons are in an atom, the more shells there are, and as the shells get further away from the nucleus, the electrons in those shells are pulled with much less force than electrons in the closer shells.

Now all that's left to remember is that as you go down the groups, the elements have bigger numbers of protons and so they have more electrons and so more shells.

Ta da!! Hope that helps!! :D
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POV: You buy a composite cup at the store. Explain the reason for your decision.
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Read 2 more answers
. What is the mass of 23.56 moles of Glucose<br> ples of Glucose - C6H1206?
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4244.48 g to the nearest hundredth.

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3 years ago
We make a basic solution by mixing 50. mL of 0.10 M NaOH and 50. mL of 0.10 M Ca(OH)2. It requires 250 mL of an HCl solution to
andreyandreev [35.5K]

<u>Answer:</u> The correct answer is Option 5.

<u>Explanation:</u>

  • To calculate the molarity of the solution after mixing 2 solutions, we use the equation:

M=\frac{n_1M_1V_1+n_2M_2V_2}{V_1+V_2}

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of the NaOH.

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of the Ca(OH)_2

We are given:

n_1=1\\M_1=0.10M\\V_1=50mL\\n_2=2\\M_2=0.1\\V_2=50mL  

Putting all the values in above equation, we get:

M=\frac{(1\times 0.1\times 50)+(2\times 0.1\times 50)}{50+50}\\\\M=0.15M

  • To calculate the molarity of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base.

We are given:

n_1=1\\M_1=?M\\V_1=250mL\\n_2=1\\M_2=0.15M\\V_2=100mL

Putting values in above equation, we get:

1\times M_1\times 250=1\times 0.15\times 100\\\\M_1=0.06M

Hence, the correct answer is Option 5.

7 0
3 years ago
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