Question

Which conversion factor do you use first to calculate the number of grams of CO 2 produced by the reaction of 50.6 g of CH 4 with O 2?

Answer 1

Answer:

Thus, first conversion of mass of methane into moles by dividing it with 16.04 g/mol

Mass =  138.63 g

Explanation:

The balanced chemical reaction is shown below:-

$CH_4+2O_2\rightarrow CO_2+2H_2O$

Firstly the moles of methane gas reacted must be calculate as:-

Given, mass of methane = 50.6 g

Molar mass of methane gas = 16.04 g/mol

The formula for the calculation of moles is:-

$Moles=\frac{Mass\ taken}{Molar\ mass}=\frac{50.6}{16.04}\ mol=3.15\ mol$

Thus, from the reaction stoichiometry,

1 mole of methane produces 1 mole of carbon dioxide

Also,

3.15 mole of methane produces 3.15 mole of carbon dioxide

Moles of $CO_2$ = 3.15 mole

Molar mass of $CO_2$ = 44.01 g/mol

Mass = Moles*Molar mass = $3.15\times 44.01$ g = 138.63 g