Question

according to Boyles law if the initial pressure and volume of a gas were five atm for the pressure and 10 mL for the volume and pressure is doubled what is the new volume

Answer 1

Answer:The new volume is 5mL

Explanation:

The formular for Boyles Law is; P1 V1 = P2 V2

Where P1 = 1st Pressure   V1 = First Volume

          P2 = 2nd Pressure V2 = Second Volume

From the question; P1 = 5atm, V1 = 10ml

                                P2 = 2 x P1 (2 x 5) = 10 atm   V2 =?  

Using the Boyles Law Formular;  P1 V1 = P2 V2, we make V2 the subject of formular;  P1 V1/ P2 = V2

∴ 5 x 10/ 10 = 5

∴ V2 = 5mL

Answer 2

Answer:

The initial volume has been halved to 5 mL

Explanation:

Step 1: Data given

Initial pressure = 5.0 atm

Initial volume = 10 mL = 0.010 L

The pressure is doubled to 10.0 atm

Step 2: Calculate the new volume

P1*V1 = P2*V2

⇒with P1 = the initial pressure of the gas = 5.0 atm

⇒with V1 = the initial volume of the gas = 10 mL = 0.010 L

⇒with P2 = the new pressure = 10.0 atm

⇒with V2 = the new volume = TO BE DETERMINED

5.0 atm * 0.010 L = 10.0 atm * V2

V2 = 0.005 L = 5 mL

Initial volume / final volume = 10 mL / 5 mL  = 2

The initial volume has been halved to 5 mL