Can i make an engine with magnets?
1 answer:
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Answer:
See explaination
Explanation:
Lets first consider the term Isentropic efficiency. The isentropic efficiency of a compressor or pump is defined as the ratio of the work input to an isentropic process, to the work input to the actual process between the same inlet and exit pressures. IN practice, compressors are intentionally cooled to minimize the work input.
Please kindly check attachment for the step by step solution of the given problem.
Answer:
A) slip(s1) = (1800 - 1750) / 1800 = 0.0277
B) 1800 rpm, 1350 rpm, 900 rpm, 450 rpm
Explanation:
Given data
frequency = 60 Hz,
Line - line rms = 440 - V
3 phase induction-motor drive
number of poles = 4
Full-load rated speed = 1750
rated torque = 40 Nm
A) The plot of torque-speed characteristics for the following values of the frequency f : 60 Hz, 45 Hz, 30 Hz, and 15 Hz is attached below
first we calculate the rated speed:
Ns =
f = 60 Hz . p (number of poles) = 4
Ns =
= 1800
full loaded rated value = 1750.
slip(s1) = (1800 - 1750) / 1800 = 0.0277
considering a linearly condition the slip is low
S1 = 0.0277
f1 = 60 Hz
hence s2 = 0.018 therefore Ns2 = 1500
B) The speeds of operation at : 60 Hz, 45 Hz, 30 Hz, 15 Hz
for 60 Hz :
Ns = = (120*60) / 4 = 1800 rpm
for 45 Hz:
Ns = 120(f) / p = (120*45) / 4 = 5400 /4 = 1350 rpm
for 30 Hz:
Ns = 120(f) / p = (120*30) / 4 = 3600 / 4 = 900 rpm
for 15 Hz:
Ns = 120(f) / p = (120*15) / 4 = 1800 / 4 = 450 rpm
