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erica [24]
4 years ago
9

Solid sodium chloride decomposes into chlorine gas and solid sodium . Write a balanced chemical equation for this reaction.

Chemistry
1 answer:
Oksana_A [137]4 years ago
5 0

Answer:

2NaCl > Cl2 + 2Na

Explanation:

2 moles of sodium chloride is irreversible to chlorine gas plus 2 moles of solid sodium

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Name two events involving electrons that can result in the formation of chemical bonds between atoms.
Alona [7]

Explanation:

Two events involving electrons are gain and loss of electrons.

When there is gain or loss of electrons between two atoms then it results in the formation of ionic bond.

Whereas when there is sharing of electrons between two atoms then it results in the formation of covalent bond.

Therefore, the chemical bonds formed can be ionic or covalent bonds.

6 0
3 years ago
200cm3 of oxygen diffuse through a porous partition in 10 seconds. How long will it take 120cm3 of chlorine to diffuse through t
Lubov Fominskaja [6]
If 200cm^3 takes 10secs then 120 will take 6secs. i hope u understood
6 0
3 years ago
Convert 123 in scientific notation
dalvyx [7]
✡ Answer: 1.23*10^2 ✡


- - Add a decimal at the end (to the right) and count till you get to the first number.
So now you have 1.23

- - Now you always want to times it by 10 to the power of how many times you moved it over, in this case, 2

Final answer: 1.23*10^2

✡Hope this helps✡


4 0
3 years ago
Read 2 more answers
Neptunium-237 undergoes a series of α-particle and β-particle productions to end up as thallium-205. How many α particles and β
Fantom [35]
<h3>Answer:</h3>

8 alpha particles

4 beta particles

<h3>Explanation:</h3>

<u>We are given;</u>

  • Neptunium-237
  • Thallium-205
  • Neptunium-237 undergoes beta and alpha decay to form Thallium-205.

We are required to determine the number of beta and alpha particles produced to complete the decay series.

  • We need to know that when a radioisotope emits an alpha particle the mass number reduces by 4 while the atomic number decreases by 2.
  • When a beta particle is emitted the mass number of the radioisotope increases by 1 while the atomic number remains the same.

In this case;

Neptunium-237 has an atomic number 93, while,

Thallium-205 has an atomic number 81.

Therefore;

²³⁷₉₃Np → x⁴₂He + y⁰₋₁e + ²⁰⁵₈₁Ti

We can get x and y

237 = 4x + y(0) + 205

237-205 = 4x

4x = 32

 x = 8

On the other hand;

93 = 2x + (-y) + 81

but x = 8

93 = 16 -y + 81

y = 4

Therefore, the complete decay equation is;

²³⁷₉₃Np → 8⁴₂He + 4⁰₋₁e + ²⁰⁵₈₁Ti

Thus, Neptunium-237 emits 8 alpha particles and 4 beta particles to become Thallium-205.

5 0
3 years ago
Based on the equation, how many grams of Br2 are required to react completely with 72.4 grams of AlCl3
svlad2 [7]

Answer:  131 g of bromine is required.

Explanation:

The balanced equation will be :

2AlCl_3+3Br_2\rightarrow 2AlBr_3+3Cl_2

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

moles of AlCl_3

\text{Number of moles}=\frac{72.4g}{133g/mol}=0.544moles

According to stoichiometry :

2 moles of AlCl_3 require  = 3 moles of Br_2

Thus 0.544 moles of AlCl_3 require=\frac{3}{2}\times 0.544=0.816moles  of Br_2

Mass of Br_2=moles\times {\text {Molar mass}}=0.816moles\times 160g/mol=131g

Thus 131 g of bromine is required.

5 0
3 years ago
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