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3 years ago

Which pair of nuclei can undergo a fusion reaction?

1 answer:

3 0

The correct answer is B. Fusion only happens between small atoms. Thus, hydrogen-2 and hydrogen-3 can undergo fusion. Fusion reaction happens when two or more nuclei combine or collide to form an element with a higher atomic number. In this process, some of the matter of the fusing nuclei is converted to energy.

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What mass of nitrogen (N2) is needed to produce 0.125 mol of ammonia (NH3)? Input a numerical answer only. N2 + 3H2 ---> 2NH:

docker41 [41]

Given the following equation: I N2(g) + 3H2(g) → _2_NH3(e) a. ... Calculate the number of grams of NH3 produced by the reaction of 5.40 g of ... C. How many grams of nitrogen are needed to produce 15.3 g of NH3?
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Very sorry if this is wrong!

5 0

3 years ago

Write 0.000000093425 in Scientific Notation with 4 significant figures.

Romashka-Z-Leto [24]

Answer: The given number in scientific notation is $9.342\times 10^{-8}$

Explanation:

Scientific notation is the notation where a number is expressed in the decimal form. This means that the number is always written in the power of 10 form. The numerical digit lies between 0.1.... to 9.9.....

If the decimal is shifting to right side, the power of 10 is negative and if the decimal is shifting to left side, the power of 10 is positive.

We are given:

A number having value = 0.000000093425

Converting this into scientific notation, we get:

$\Rightarrow 0.000000093425=9.342\times 10^{-8}$

Hence, the given number in scientific notation is $9.342\times 10^{-8}$

6 0

4 years ago

Read 2 more answers

If i have 4 moles of a gas ata pressure of 5.2 atm and a volume of 15 liters, what is the temperature?

kompoz [17]

Answer:

237.5 K.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm (P = 5.2 atm).

V is the volume of the gas in L (V = 15.0 L).

n is the no. of moles of the gas in mol (n = 4.0 mol).

R is the general gas constant (R = 0.0821 L.atm/mol.K),

T is the temperature of the gas in K (T = ??? K).

∴ T = PV/nR = (5.2 atm)(15.0 L)/(4.0 mol)(0.0821 L.atm/mol.K) = 237.5 K.

5 0

3 years ago

What is the oxidation state for a Mn atom? (1) 0 (2) +7 (3) +3 (4) +4

ss7ja [257]

Answer : The correct option is, (1) 0

Explanation :

Oxidation state or oxidation number : It represent the number of electrons lost or gained by the atoms of an element in a compound.

Oxidation numbers are generally written with sign (+ and -) first and then the magnitude.

When the atoms are present in their elemental state then the oxidation number will be zero.

As per question, 'Mn' atom is a free element that means it is present in their elemental state then the oxidation state will be zero.

Hence, the correct option is, (1) 0

5 0

3 years ago

Calculate the total amount of energy required to change 10.0 g of water from 35.0 degrees Celsius to 110. degrees Celsius.

Makovka662 [10]

Answer:

The total amount of energy required is 25,515.2 J.

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

When a system absorbs (or gives up) a certain amount of heat, it can happen that:

experience a change in its temperature, which involves sensible heat,
undergoes a phase change at constant temperature, or latent heat.

To calculate the latent heat the formula is used:

Q = m. L

Where

Q: amount of heat
m: mass
L: latent heat

To calculate sensible heat the following formula is used:

Q = m. c. ΔT

where:

Q: amount of sensible heat
m: body mass
c: specific heat of the substance
ΔT: temperature range

In this case, you have in the first place a heat to raise the temp of the water from 35.0 C to 100 C, where the specific heat value for water is 4.184 $\frac{J}{g*C}$ :

q1 = m*c*(Tfinal-Tinitial)

q1 = 10.0 g *(4.184 $\frac{J}{g*C}$ )* (100 - 35.0 C) = 2719.6 J

Now you have the heat to vaporize the water, where the heat of vaporization is 2259.36 $\frac{J}{g}$ :

q2 = m*(heat of vaporization)

q2 = 10.0 g*(2259.36 $\frac{J}{g}$ ) = 22593.6 J

Finally, you have the heat to raise temp of steam to 110 C, where the specific heat value for steam is 2.02 $\frac{J}{g*C}$ :

q3 = m*c*(Tfinal-Tinitial)

q3 = 10.0 g*(2.02 $\frac{J}{g*C}$ )*(110-100 C) = 202 J

The total amount of energy can be calculated as:

Q= q1 + q2 + q3

Q= 2719.6 J + 22593.6 J + 202 J

Q=25,515.2 J

The total amount of energy required is 25,515.2 J.

5 0

3 years ago