Answer:
The luminosity remains the same, but the apparent brightness is decreased by a factor of four.
Explanation:
The apparent brightness, F = L/4πr² where L = luminosity and r = distance between us and the star.
Since L is independent of the distance between us and the star, it is constant, then
F ∝ 1/r²
So, F₁/F₂ = r₂²/r₁² where F₁ = apparent brightness at r₁ and F₂ = apparent brightness at r₂
If the distance is doubled, that is r₂ = 2r₁, then
F₁/F₂ = r₂²/r₁²
F₁/F₂ = (2r₁)²/r₁²
F₁/F₂ = 4r₁²/r₁²
F₁/F₂ = 4
F₂ = F₁/4
So, since the luminosity is constant, <u>the luminosity remains the same, but the apparent brightness is decreased by a factor of four.</u>
Answer: It was a big learning platformed and influenced millions of people. Without it we wouldnt be where we are today
Explanation:
Answer:
5 seconds
Explanation:
The vertical position of the ball will be given by the equation
df = do + vo t + 1/2 a t^2 df = final position = 0 ( on the ground
do = original position ( 25 m )
vo = original velocity (+ 20 m/s)
a = - 10 m/s^2
So this becomes
0 = 25 + 20 t - 1/2 (10)t^2
= - 5 t^2 +20 t + 25 Use Quadratic Formula a = -5 b=20 c = 25
to find the positive value of t = 5 seconds
Yeah I’m guessing because I need help also