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d1i1m1o1n [39]
3 years ago
14

If a sample shows only one-fourth of its estimated original quantity of 14c, how old is it? think about half-lives; don't try to

just plug into the decay equation. (you shouldn't need to plug into it at all for this problem.
Physics
1 answer:
kykrilka [37]3 years ago
6 0
The half-life of C-14 is approximately 5730 years. This means that the quantity contained in the sample becomes half of its original value after 5730 years. After another 5730 years, the quantity becomes 1/4 of its original value, and so on.

In our problem, the s<span>ample shows only one-fourth of its estimated original quantity, this means that  its age is twice 5730 years:
</span>t=5730 y+5730 y=11460 y<span>
</span>
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