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3 years ago

How would the period of a simple pendulum be affected if it were located on the moon instead of the earth?

Physics

1 answer:

OlgaM077 [116]3 years ago

5 0

Answer:

On moon time period will become 2.45 times of the time period on earth

Explanation:

Time period of simple pendulum is equal to $T=2\pi \sqrt{\frac{l}{g}}$ ....eqn 1 here l is length of the pendulum and g is acceleration due to gravity on earth

As when we go to moon, acceleration due to gravity on moon is $\frac{1}{6}$ times os acceleration due to gravity on earth

So time period of pendulum on moon is equal to

$T_{moon}=2\pi \sqrt{\frac{l}{\frac{g}{6}}}=2\pi \sqrt{\frac{6l}{g}}$ --------eqn 2

Dividing eqn 2 by eqn 1

$\frac{T_{moon}}{T}=\sqrt{\frac{6l}{g}\times \frac{g}{l}}$

$T_{moon}=\sqrt{6}T=2.45T$

So on moon time period will become 2.45 times of the time period on earth

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3 years ago

What are the difference between conductor and insulator?

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Answer:

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3 years ago

a 45 kg ice skater initially skating at a velocity of 3 m/s speeds up to a velocity of 5 m/s. calculate the difference in the ma

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Answer: 90 kgm/s

Explanation:

The momentum (linear momentum) $p$ is given by the following equation:

$p=m.V$

Where:

$m=45 kg$ is the mass of the skater

$V$ is the velocity

In this situation the skater has two values of momentum:

Initial momentum: $p_{1}=m.V_{1}$

Final momentum: $p_{2}=m.V_{2}$

Where:

$V_{1}=3 m/s$

$V_{1}=5 m/s$

So, if we want to calculate the difference in the magnitude of the skater's momentum, we have to write the following equation(assuming the mass of the skater remains constant):

$p=p_{2}-p_{1}=m.V_{2}-m.V_{1}$

$p=m(V_{2}-V_{1})$

$p=45 kg(5 m/s - 3 m/s)$

Finally:

$p=90 kgm/s$

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4 years ago

Read 2 more answers

I need help, ASAP, I know what thermal energy is, but how does a skater use it when on the track?

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Answer: Looked it up but

Explanation:

When the skater lands on the track, the vertical component of his kinetic energy is converted to thermal energy. You can do experiments where there is no loss to thermal energy (only PE and KE conversions) by turning friction off and by making sure the skater doesn't leave the track.

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3 years ago

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Hope this helps

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4 years ago