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Dmitry_Shevchenko [17]
3 years ago
15

Suppose you are conducting an experiment concerning gravity's effects on falling objects, and you want to minimize air resistanc

e.
Which of these would be the MOST useful and practical way to do this?
A)
Use larger objects.
B)
Use extremely dense objects.
O
Conduct the experiment in a vacuum.
D)
Conduct the experiment at various altitudes.
Physics
1 answer:
Vladimir79 [104]3 years ago
7 0
Answer: C) Conduct the experiment in a vacuum.
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Physics question, please help?
Ludmilka [50]

0.4823 m/s

The initial velocity u1 of the ball=0

From the law of conservation of linear momentum.

m1u1+m2u2=m1v1+m2v2

(160×0)+(170×u1)=(160×0.3)+(170×0.2)

u1=0.4823m/s

6 0
3 years ago
What is demonstrated by water moving up a straw?
Alja [10]
<span>The answer is C: water is drawn up a straw by cohesion and adhesion. Water molecules stick to one another and the walls of the straw, just like in a capillary.
Cohesion is the attractive force between like materials (between water
molecules).
Adhesion is the attractive force between twounlike materials (such as between
water and a solid container).
Capillary action is the tendency of a liquid to rise innarrow tubes or small openings as a result of adhesion and cohesion.
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8 0
3 years ago
Read 2 more answers
Do electrons have more room to move along a thick or thin wire?
PolarNik [594]

Answer:

Got it from g00gle: Similarly, electrons flow more easily through a thick wire than they flow through a thin wire of the same material. Resistance is greater in a longer wire because the charges travel farther. As temperature increases, a metal's resistance increases because electrons collide more often.

Explanation:

3 0
3 years ago
Two gears are connected. Gear A has 10 teeth, while gear b has 40 teeth. If gear B turns at 10 rpms, how fast will gear a turn?
SVETLANKA909090 [29]

Answer:

w₁ =  40 rpm

Explanation:

Number of teeth of gear A = 10

Number of teeth of gear B =  40

Speed of gear B = w₂ = 10 rpm

Speed of gear A = w₁ = ?

Gear ratio is given by:

N₁/N₂ = w₂ / w₁

w₁ = N₂/N₁ * w₂

⇒ w₁ = 40/10 * 10

⇒ w₁ =  40 rpm

4 0
3 years ago
You need to figure out how high it is from the 3rd floor of Keck science building to the ground. You know that the distance from
Tcecarenko [31]

Answer:1.624 m

Explanation:

Given

height of 2nd floor =5 m

time recorded is 0.58 sec

Let h be the height of third floor above 2 nd floor

h=ut+\frac{at^2}{2}

here u=0

t=time taken to cover height h

h=\frac{gt^2}{2}   ----------1

Now time taken to complete whole building length

h+5=\frac{g(t+0.58)^2}{2}  ----------2

Subtract 1 form 2

5=\frac{g(2t+0.58)(0.58)}{2}

Taking gravity g=1 m/s^2

1=(2t+0.58)(0.58)

t=0.57 s

Substitute the value of t in 1

h=1.624 m

4 0
3 years ago
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