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dsp73
3 years ago
6

Which part of an atom makes up most its volume

Physics
1 answer:
VikaD [51]3 years ago
4 0

Hi! The inner most part of the atom (which is most of the atom) is occupied by electrons, therefore it’d take of most of its volume. Have a nice day!

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In lab, your instructor generates a standing wave using a thin string of length L = 1.65 m fixed at both ends. You are told that
erik [133]

Answer:

On the standing waves on a string, the first antinode is one-fourth of a wavelength away from the end. This means

\frac{\lambda}{4} = 0.275~m\\\lambda = 1.1~m

This means that the relation between the wavelength and the length of the string is

3\lambda/2 = L

By definition, this standing wave is at the third harmonic, n = 3.

Furthermore, the standing wave equation is as follows:

y(x,t) = (A\sin(kx))\sin(\omega t) = A\sin(\frac{\omega}{v}x)\sin(\omega t) = A\sin(\frac{2\pi f}{v}x)\sin(2\pi ft) = A\sin(\frac{2\pi}{\lambda}x)\sin(\frac{2\pi v}{\lambda}t) = (2.45\times 10^{-3})\sin(5.7x)\sin(59.94t)

The bead is placed on x = 0.138 m. The maximum velocity is where the derivative of the velocity function equals to zero.

v_y(x,t) = \frac{dy(x,t)}{dt} = \omega A\sin(kx)\cos(\omega t)\\a_y(x,t) = \frac{dv(x,t)}{dt} = -\omega^2A\sin(kx)\sin(\omega t)

a_y(x,t) = -(59.94)^2(2.45\times 10^{-3})\sin((5.7)(0.138))\sin(59.94t) = 0

For this equation to be equal to zero, sin(59.94t) = 0. So,

59.94t = \pi\\t = \pi/59.94 = 0.0524~s

This is the time when the velocity is maximum. So, the maximum velocity can be found by plugging this time into the velocity function:

v_y(x=0.138,t=0.0524) = (59.94)(2.45\times 10^{-3})\sin((5.7)(0.138))\cos((59.94)(0.0524)) = 0.002~m/s

4 0
3 years ago
The wetter the surface, the friction
allochka39001 [22]
Answer: Water can either increase or decrease the friction between surfaces.
7 0
3 years ago
Humans and fish brains are similar because they both have a?
velikii [3]

Answer:

it is because they can store and retrieve informatiion just like human beings

4 0
3 years ago
Why does atmospheric pressure decrease with altitude.
ella [17]

Answer:

<em>Earth's gravity pulls air as close to the surface as possible. ... As altitude increases, the amount of gas molecules in the air decreases—the air becomes less dense than air nearer to sea level. This is what meteorologists and mountaineers mean by "thin air." Thin air exerts less pressure than air at a lower altitude.</em>

5 0
2 years ago
Starting from rest, a 88-kg firefighter slides down a fire pole. The average frictional force exerted on him by the pole has a m
Cloud [144]

Answer:h=7.22 m

Explanation:

Given

mass of firefighter m=88 kg

Frictional Force F=800 N

average speed at bottom v=3.2 m/s

Let h be the height of Pole

net force on Firefighter is

F_{net}=88\times 9.8-800=62.4

therefore net acceleration is

a_{net}=\frac{62.4}{88}=0.709 m/s^2

using v^2-u^2=2ah

here v=3.2 m/s

u=0

(3.2)^2-0=2\times 0.709\times h

h=\frac{10.24}{1.418}

h=7.22 m

3 0
3 years ago
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