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german
3 years ago
15

To see how deep a well is you drop a rock in. The rock hits the water 10 seconds later.

Physics
1 answer:
Karolina [17]3 years ago
6 0

Answer:

490m

Explanation:

Given parameters:

     Time taken = 10s

Unknown:

Depth of the well = ?

Solution:

To find the depth of the well, we apply the appropriate motion equation:

     h = ut + \frac{1}{2}gt²

h is the depth

u is the initial velocity

g is the acceleration due to gravity  = 9.8m/s²

t is the time taken

 Input the parameters and solve;

 The ball was dropped from rest; u = 0

      h  =  \frac{1}{2}gt²

      h  =   \frac{1}{2} x 9.8 x 10²  = 490m

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How could rescue workers use squeezing or compressing to get energy to their flashlights during rescue missions?
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Explanation:

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A small truck has a mass of 2145 kg. How much work is required to decrease the speed of the vehicle from 25.0 m/s to 12.0 m/s on
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Answer:

The work required is -515,872.5 J

Explanation:

Work is defined in physics as the force that is applied to a body to move it from one point to another.

The total work W done on an object to move from one position A to another B is equal to the change in the kinetic energy of the object. That is, work is also defined as the change in the kinetic energy of an object.

Kinetic energy (Ec) depends on the mass and speed of the body. This energy is calculated by the expression:

Ec=\frac{1}{2} *m*v^{2}

where kinetic energy is measured in Joules (J), mass in kilograms (kg), and velocity in meters per second (m/s).

The work (W) of this force is equal to the difference between the final value and the initial value of the kinetic energy of the particle:

W=\frac{1}{2} *m*v2^{2}-\frac{1}{2} *m*v1^{2}

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W=\frac{1}{2} *2145 kg*((12\frac{m}{s} )^{2}-(25\frac{m}{s} )^{2})

W= -515,872.5 J

<u><em>The work required is -515,872.5 J</em></u>

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