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anygoal [31]
3 years ago
15

What will most likely happen in the absence of a cell membrane?

Chemistry
2 answers:
alisha [4.7K]3 years ago
5 0

Answer: D - Substances will pass in and out of the cell in an uncontrolled manner

Explanation:

I am taking the quiz right now :)

Zielflug [23.3K]3 years ago
3 0
<h2>Answer:</h2>

The correct answer is option D which is substances will pass in and out of the cell in an uncontrolled manner.

<h3>Explanation:</h3>
  • Cell membrane is outer organelle in the cell, it is responsible for the transport of materials into and out to the cell through osmosis and active transport.
  • In the absence of the cell membrane, there will not be control of transport of a materials to the cell.
  • Energy production is the task of mitochondria and food storage is the function of vacuoles.
  • Photosynthesis takes place on the chloroplasts.
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3 years ago
Compound is a clear liquid with a strong pleasantly fruity smell. If cooled it freezes at about. In the solid state it does not
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Compound 3 is a clear liquid with a strong pleasantly fruity smell. If cooled it freezes at about −10°C. In the solid state it does not conduct electricity. ... It dissolves slightly in water, and a solution of 2g in 100mL of water doesn't change the electrical conductivity of the water.

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7 0
2 years ago
Read 2 more answers
Is heated water more or less dense than the melted snow And rainwater
san4es73 [151]

Answer:

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Explanation:

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2 years ago
The vapor pressure of benzene is 73.03 mm Hg at 25°C. How many grams of estrogen (estradiol), C18H24O2, a nonvolatile, nonelectr
alexira [117]

Answer:

14.9802 grams of estrogen must be added to 216.7 grams of benzene.

Explanation:

The relative lowering of vapor pressure of solution containing non volatile solute is equal to mole fraction of solute.

\frac{p_o-p_s}{p_o}=\frac{n_2}{n_1+n_2}

Where:

p_o = Vapor pressure of pure solvent

p_s = Vapor pressure of the solution

n_1 = Number of moles of solvent

n_2 = Number of moles of solute

p_o = 73.03 mmHg

p_s= 71.61 mmHg

n_1=\frac{216.7 g}{78.12 g/mol}=2.7739 mol

\frac{73.03 mmHg-71.61 mmHg}{73.03 mmHg}=\frac{n_2}{2.7739 mol+n_2}

n_2=0.05499 mol

Mass of 0.05499 moles of estrogen :

= 0.05499 mol × 272.4 g/mol = 14.9802 g

14.9802 grams of estrogen must be added to 216.7 grams of benzene.

6 0
3 years ago
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