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-BARSIC- [3]
3 years ago
13

Describe the basic structure of the atom

Chemistry
1 answer:
aleksley [76]3 years ago
7 0

An atom has a nucleus and is made up of protons neutrons and electrons

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. What is the main gas found in the air we breathe?
laiz [17]

Answer:

Nitrogen

Explanation:

4 0
4 years ago
when you cook food like eggs or potatoes this is a chemical change when candle burns the wick of the candle and wax turn into no
finlep [7]

When you cook food like eggs, this is a chemical change. Agree.

The runny egg turns into a solid. One type of matter must be changing into another type

When you cook food like potatoes, this is a chemical change. Agree.

Boiling potatoes causes changes in the structure of the starch. Higher heat as in baking, roasting, or frying causes the development of a harder crust on the potato. This suggests that chemical changes have taken place.

When a candle burns, the wick of the candle and wax turn into nothing. Disagree.

The <em>Law of Conservation of Mass</em> says that <em>you can’t turn matter into nothing</em>. What must be happening is that the wick and the wax are changing into other substances that we can’t see, such as colourless gases of carbon dioxide and water vapour.

5 0
3 years ago
A food product contains 15 g of carbohydrates, 5 g of protein and 4 g of fat. How many calories are in one serving of this produ
Basile [38]

Answer: 116 calories of energy

Explanation:

A calorie is a non-standard unit of energy.

On combustion,

1 gram Carbohydrates = 4 calories,

1 gram protein = 4 calories,

1gram fat = 9 calories.

Therefore,

15 grams of carbohydrates = (15*4) = 60

5 grams of protein = (5*4) = 20

4 grams of fats = (4*9) = 36

Then add up: 60 + 20 + 36 = 116 calories of energy

4 0
3 years ago
A pencil sharpener contains which simple machine
Whitepunk [10]
Wheel and axle its spins
3 0
3 years ago
Read 2 more answers
What is the solubility (in g/L) of calcium fluoride at 25°C? The solubility product constant for calcium fluoride is 3.4 × 10–11
PilotLPTM [1.2K]

<u>Answer:</u> The correct answer is Option b.

<u>Explanation:</u>

The balanced equilibrium reaction for the ionization of calcium fluoride follows:

CaF_2\rightleftharpoons Ca^{2+}+2F^-

                s       2s

The expression for solubility constant for this reaction will be:

K_{sp}=[Ca^{2+}][F^-]^2

We are given:

K_{sp}=3.4\times 10^{-11}

Putting values in above equation, we get:

3.4\times 10^{-11}=(s)\times (2s)^2\\\\3.4\times 10^{-11}=4s^3\\\\s=2.04\times 10^{-4}mol/L

To calculate the solubility in g/L, we will multiply the calculated solubility with the molar mass of calcium fluoride:

Molar mass of calcium fluoride = 78 g/mol

Multiplying the solubility product, we get:

s=2.04\times 10^{-4}mol/L\times 78g/mol=159.12\times 10^{-4}g/L=0.015g/L

Hence, the correct answer is Option b.

3 0
3 years ago
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