Answer:
Here’s your answer!
Step-by-step explanation:
2005 as a percent is 200500%!
Hope this helps
Dont forget to smash that heart at the bottom <3
Plz Mark Brainliest
Need help solving future problems like this? Use GetEasySolution.com for a calculator that works for decimals,percents and more! ( I am not with them but the calculator did help me a while back so here’s a recommendation)
Have a great day,youre amazing!
Hey Jinx :)
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Note that a decay has a rate between 0 and 1, and a growth as a rate of 1 or higher.
y = 1/2(1 + 0.03)^t → y = 1/2(1.03)^t (Rate is more then 0) GROWTH
y = 0.3(0.95)^t → (Rate is between 0 and 1) DECAY
y = ((1+0.03)^1/2)^2t → y = y = 1.014^2t (Rate is more then 0) GROWTH
y = 200(0.73)^t → (Rate is between 0 and 1) DECAY
y = 4(1/4)^t → (Rate is between 0 and 1) DECAY
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Hope This Helped! Good Luck!
Answer:
y=4x-8.5
Step-by-step explanation:
Use point- slope form, since you are given one point and one slope.
y-y₁=m(x-x₁)
Plug coordinates and slope in.
y-(-1/2)=4(x-2)
Solve
y+1/2=4x-8
y=4x-8.5
Answer:
His money earned $36 after 3 months
Step-by-step explanation:
* Lets revise the rules of simple interest
- Simple Interest Equation (Principal + Interest)
A = P(1 + rt)
- Where:
• A = Total amount (principal + interest) future amount
• P = Principal Amount
• I = Interest Amount
• r = Rate of Interest per year in decimal; r = R/100
• t = Time Period involved
* To calculate the interest I use the formula
I = P × r × t
* Lets solve the problem
- The rate is annual
- The interest calculated after 3 months
∴ I = P × R/100 × t/12
∵ P = $3600.00
∵ R = 4%
∵ t = 3 month
∴ I = 3600.00 × 4/100 × 3/12 = $36
* His money earned $36 after 3 months
In order to calculate the amount, we simply substitute the number of years into x in both equations.
After 3 years:
f(3) = 5(3) + 150
= $165
g(3) = 150 * 1.03⁽³⁾
= $163.90
After 10 years:
f(10) = 5(10) + 150
= $200
g(10) = 150 * 1.03⁽¹⁰⁾
= $201.59
After three years, the first account has more money but after ten years, the second account has more money.
