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uysha [10]
3 years ago
5

is the following sentence true or false? the faster the particles of a substance are moving, the more energy they have.

Physics
2 answers:
ryzh [129]3 years ago
3 0
Im pretty sure false but not 100% :) 
Ket [755]3 years ago
3 0
True if they keep moving faster the more energy they get it's like kids they have unlimited energy and the more they move the more they have fun, Fun= energy
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The vector quantity that defines the distance and direction between two positions. It is a change in your position.
lilavasa [31]

I believe you're talking about displacement. It's a directional vector that depicts the movement of a point between two instances.

4 0
3 years ago
A uniform cubical crate is 0.740 m on each side and weighs 600 N. It rests on the floor with one edge against a very small, fixe
Sindrei [870]

Answer:

H = 0.673

Explanation:

given,

side of cubical crate = 0.74

weight of the crate = 600 N

magnitude of force = 330 N

the Horizontal distance of its Center of mass

= 0.74/2

= 0.37

Let the required Height be H

By Balancing the Torques, we get

H x 330 N = 0.37 x 600

330 H = 222

H = 0.673

hence, the height above the floor where force is acting is equal to 0.673 m

6 0
3 years ago
QUICCCKKKKK!!!!!!!!!!Stimulus discrimination occurs when an organism generalizes one consequence to many stimuli similar to the
timama [110]
False i just took the test and put true as a guess but got it wrong so it is false

please give me a brainlies
7 0
3 years ago
Read 2 more answers
One method used to determine the volume of solids and liquids is displacement.
andreyandreev [35.5K]
A. True. You can use displacement to determine the volume of solids and liquids.
4 0
3 years ago
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Your answer should be precise to 0.1 m/s. Use a gravitational acceleration of 10 m/s/s. At it lowest point, a pendulum is moving
saw5 [17]

Explanation:

It is given that,

Speed, v₁ = 7.7 m/s

We need to find the velocity after it has risen 1 meter above the lowest point. Let it is given by v₂. Using the conservation of energy as :

\dfrac{1}{2}mv_1^2=\dfrac{1}{2}mv_2^2+mgh

v_2^2=v_1^2-2gh

v_2^2=(7.7)^2-2\times 10\times 1

v_2=6.26\ m/s

So, the velocity after it has risen 1 meter above the lowest point is 6.26 m/s. Hence, this is the required solution.

4 0
4 years ago
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