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3 years ago

5

is the following sentence true or false? the faster the particles of a substance are moving, the more energy they have.

2 answers:

ryzh [129]3 years ago

3 0

Im pretty sure false but not 100% :)

Ket [755]3 years ago

3 0

True if they keep moving faster the more energy they get it's like kids they have unlimited energy and the more they move the more they have fun, Fun= energy

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A ball is kicked at an angle of 35 degrees with the ground. What should be the initial velocity of the ball so that it hits a ta

pashok25 [27]

Answer:

18.5 M/S

Explanation:

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6 0

4 years ago

The first artificial satellite to orbit the Earth was Sputnik I, launched October 4, 1957. The mass of Sputnik I was 83.5 kg, an

9966 [12]

Answer:

$-4.941*10^8J.$

Explanation:

To solve this exercise it is necessary to take into account the concepts related to gravitational potential energy, as well as the concept of perigee and apogee of a celestial body.

By conservation of energy we know that,

$\Delta U = \Delta_{perogee}-\Delta_{Apogee}$

Where,

$U= \frac{-GmM_e}{r}$

Replacing

$\Delta U = \frac{-GmM_e}{r_p}- \frac{-GmM_e}{r_a}$

$\Delta U = GmM_e (\frac{1}{r_A}-\frac{1}{r_p})$

Our values are given by,

$m = 85.5Kg$

$M_e = 5.97*10^{24}Kg$

$r_A = 7330Km$

$r_p = 6610Km$

$G = 6.67*10^{-11}Nm^2/Kg^2$

Replacing at the equation,

$\Delta U = (6.67*10^{-11})(85.5)(5.97*10^{24}) (\frac{1}{7330}-\frac{1}{6610})$

$\Delta U = -4.941*10^8J$

Therefore the Energy necessary for Sputnik I as it moved from apogee to perigee was $-4.941*10^8J.$

4 0

3 years ago

Which property of a substance is not affected by physical changes?

Leokris [45]

The answer is A. Reactivity

hope this helps

8 0

4 years ago

An air bubble of volume 20 cm³ is at the bottom of a lake 40 m deep, where the temperature is 4.0°C. The bubble rises to the sur

soldi70 [24.7K]

Answer:

100 cm³

Explanation:

Use ideal gas law:

PV = nRT

where P is absolute pressure, V is volume, n is number of moles, R is ideal gas constant, and T is absolute temperature.

n and R are constant, so:

P₁V₁/T₁ = P₂V₂/T₂

If we say point 1 is at 40m depth and point 2 is at the surface:

P₂ = 1.013×10⁵ Pa

T₂ = 20°C + 273.15 = 293.15 K

P₁ = ρgh + P₂

P₁ = (1000 kg/m³ × 9.8 m/s² × 40 m) + 1.013×10⁵ Pa

P₁ = 4.933×10⁵ Pa

T₁ = 4.0°C + 273.15 = 277.15 K

V₁ = 20 cm³

Plugging in:

(4.933×10⁵ Pa) (20 cm³) / (277.15 K) = (1.013×10⁵ Pa) V₂ / (293.15 K)

V₂ = 103 cm³

Rounding to 1 sig-fig, the bubble's volume at the surface is 100 cm³.

6 0

3 years ago

Object A attracts object B with a gravitational force of 10 newtons from a given distance. If the distance between the two objec

balandron [24]

By definition, the gravitational force is given by:

$F = G(\frac{m1m2}{r^2})$

Where,

G: gravitational constant

m1: mass of object 1

m2: mass of object 2

r: distance between objects:

We know that the force is equal to 10N:

$G(\frac{m1m2}{r^2}) = 10$

If the distance is double we have:

$F = G(\frac{m1m2}{(2r)^2}) = G(\frac{m1m2}{4r^2}) = \frac{1}{4}G(\frac{m1m2}{r^2})$

$\frac{1}{4}(10) = 2.5$

Therefore, the new force is:

2.5 newtons

Answer:

the changed force of attraction between them is:

A. 2.5 newtons

7 0

3 years ago

Read 2 more answers