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4 years ago

What is the function of a neurotransmitter?

Chemistry

1 answer:

alexandr402 [8]4 years ago

6 0

The main function of a neurotransmitter is to communicate information throughout brain and and body

Hope this helps!

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An ideal gas has a volume of 5.00L under a pressure of 1.00 atm and a temperature of 10.0 K. If the temperature is changed to 10

tigry1 [53]

Answer:

6.25 L

Explanation:

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

7 0

3 years ago

Write a chemical equation that shows the release of hydroxide ions as each of these bases dissolves in water.

Zarrin [17]

KOH -------> K+ OH-
Ba(OH)2 ------> Ba+2. 2OH-

5 0

4 years ago

Which of the following are examples of chemical changes? Select all that apply.

Travka [436]

A B and C are all chemical changes. paper tearing is not.

6 0

3 years ago

A portion of the periodic table is shown above Which element on the periodic table has properties that are most similar to those

liq [111]

Most similar would be phosphorus, because they have the same number of electrons in their outer orbitals, thus they create the same ions, and react with elements in a similar fashion.
Different would probably be aluminum. Aluminum is a metal while nitrogen is a non-metal, as seen by the colors above. Also, aluminum creates a positive ion (losses electrons to become stable) while nitrogen creates a negative ion (gains electrons to become stable)
Hope this helps!!

3 0

3 years ago

Read 2 more answers

Reynolds number E. What is the mean velocity u. (ft/s) and the Reynolds number Re = pu., D/ for 35 gpm (gallons per minute) of w

Novay_Z [31]

Answer:

The mean velocity is 13 ft/s.

The Reynolds number is 88,583 and it is dimensionless.

Explanation:

We have water flowing in a pipe of 1.05 in diameter.

The density is ρ=62.3 lb/ft and the viscosity is 1.2 cP.

The mean velocity can be calculated as

$u=\frac{Q}{A}=\frac{Q}{\pi*D^2/4}=\frac{35gpm }{3.14*(1.05in)^2/4}\\\\ u=\frac{35}{0.865}*\frac{gal}{min}\frac{1}{in^2}*\frac{231in^3}{1gal}*\frac{1}{60s} \\\\ u=156\,in/s=13\,ft/s$

The Reynolds number now can be calculated for this flow as

$Re=\frac{\rho*u*D}{\mu}$

being ρ: density, u: mean velocity of the fluid, D: internal diameter of the pipe and μ the dynamic viscosity.

To simplify the calculation, we can first make all the variables have coherent units.

<em>Viscosity</em>

$\mu=1.2cP=\frac{1.2}{100}\frac{g}{cm*s}*\frac{1lb}{453.6g}*\frac{30.48cm}{1ft}= 0.0008\frac{lb}{ft*s}$

<em>Diameter</em>

$D=1.05in*(\frac{1ft}{12in} )=0.0875ft$

Then the Reynolds number is

$Re=\frac{\rho*u*D}{\mu}\\\\Re=62.3\frac{lb}{ft^3}*13\frac{ft}{s} *0.0875ft*\frac{1}{0.0008}*\frac{ft*s}{lb}\\\\Re=88,583$

8 0

3 years ago