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makvit [3.9K]
3 years ago
8

Which of these is a mixture? A. carbon B. carbon dioxide C. air D. oxygen

Chemistry
1 answer:
Ilya [14]3 years ago
7 0
Air is a mixture of approximately 80% nitrogen, 20% oxygen and a small amount of many other gases.
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Explain difference in melting points for the elements Na and Mg
Savatey [412]

Answer:

magnesium has a greater charge, there will be greater attraction between delocalised electrons and the positively charged ion.

Explanation:

I did this once and got it right I hope you get it right too

6 0
3 years ago
How many milliliters of manganese metal, with a density of 7.43 g/mL, would be needed to produce 21.7 grams of hydrogen gas in t
Alla [95]
First compute the number of grams of manganese metal required to make 21.7 grams of H2. 
21.7 g H2 x (1 mole H2/ 2 g H2) x (1 mole Mn/1 mol H2) x (55 grams Mn/1 mol Mn) = 596.75 grams 
Now density = mass/volume 
7.43 = 596.75/volume 
volume = 596.75/7.43 = 80.31 mL 
80.31 mL is the amount of manganese needed.
3 0
3 years ago
What is the density of an unknown substance that has a mass of 30 g and a volume of 10mL? a. 300 g/mL b. 30 g/mL c.3 g/mL d.1 g/
balu736 [363]

Answer:

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6 0
2 years ago
A mirage is caused by the bending of light rays as they pass through air layers of different densities.
taurus [48]

Answer:

T. True

Explanation:

The correct answer would be yes, this statement is true. A mirage is cause by refraction.

7 0
2 years ago
A gas cylinder contains 2.0 mol of gas X and 6.0 mol of gas Y at a total pressure of 2.1 atm. What is the partial pressure of ga
vivado [14]

Answer :  The partial pressure of X and Y gases are, 0.525 and 1.575 atm respectively.

Explanation : Given,

Moles of X = 2.0 mole

Moles of Y = 6.0 mole

Total pressure = 2.1 atm

Now we have to calculate the mole fraction of X and Y.

\text{Mole fraction of }X=\frac{\text{Moles of }X}{\text{Moles of }X+\text{Moles of }Y}

\text{Mole fraction of }X=\frac{2.0}{2.0+6.0}=0.25

and,

\text{Mole fraction of }Y=\frac{\text{Moles of }Y}{\text{Moles of }X+\text{Moles of }Y}

\text{Mole fraction of }Y=\frac{6.0}{2.0+6.0}=0.75

Now we have to calculate the partial pressure of X and Y.

According to the Raoult's law,

p_i=X_i\times p_T

where,

p_i = partial pressure of gas

p_T = total pressure of gas  = 2.1 atm

X_i = mole fraction of gas

p_{X}=X_{(X)}\times p_T

p_{X}=0.25\times 2.1atm=0.525atm

and,

p_{Y}=X_{(Y)}\times p_T

p_{Y}=0.75\times 2.1atm=1.575atm

Thus, the partial pressure of X and Y gases are, 0.525 and 1.575 atm respectively.

4 0
3 years ago
Read 2 more answers
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