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Ghella [55]
3 years ago
5

What causes seasons to occur?

Physics
2 answers:
Semmy [17]3 years ago
7 0

Answer:

C

Explanation:

I believe that it's C

LUCKY_DIMON [66]3 years ago
3 0
It’s C I hope it helps you
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The table represents the forces on four objects, with directions.
noname [10]

b. Objects W and Y have balanced forces, and objects X and Z have unbalanced forces.

Explanation:

An object is said to have balanced forces if the resultant of the forces acting on it is zero. This situation occurs, for instance, when the sum of the forces on the vertical direction is zero and the sum of the forces on the horizontal direction is zero as well.

For the objects in the table, we see that:

- Object W: the resultant on the vertical direction is zero, because we have two opposite forces with same magnitude (30 N), so they cancel each other. Also, the resultant on the horizontal direction is zero, because we have two opposite forces with same magnitude (20 N), so they cancel each other.

- Object X: the resultant on the vertical direction is zero, because we have two opposite forces with same magnitude (15 N), so they cancel each other. However, the resultant on the horizontal direction is NOT zero, because we have two opposite forces but with different magnitude (35 N and 25 N), so they do not cancel each other, and they make a net force of 35 N - 25 N=10 N.

- Object Y:  the resultant on the vertical direction is zero, because we have two opposite forces with same magnitude (60 N), so they cancel each other. Also, the resultant on the horizontal direction is zero, because we do not have forces along this direction.

- Object Z: the resultant on the vertical direction is zero, because we have two opposite forces with same magnitude (45 N), so they cancel each other. However, the resultant on the horizontal direction is NOT zero, because the net force is 22 N, not balanced from the other direction.

Therefore, objects W and Y have balanced forces, and objects X and Z have unbalanced forces.

5 0
3 years ago
Read 2 more answers
What are the highlands of the moon called?<br> A) Maria<br> B) Terrae<br> C)Regolith<br> D)Crater
marissa [1.9K]

Answer:

C)Regolith

PLEASE GIVE BRAINLIEST

8 0
3 years ago
Read 2 more answers
In addition to their remarkable top speeds of almost 60 mph, cheetahs have impressive cornering abilities. In one study, the max
Sav [38]

Answer:

the minimum value of the coefficient of static friction between the ground and the cheetah's feet is 1.94

Explanation:

Given that ;

the top speed of Cheetahs is almost 60 mph

In cornering abilities ; the maximum centripetal acceleration of a cheetah was measured to be = 19 m/s^2

The objective of this question is to determine the what minimum value of the coefficient of static friction between the ground and the cheetah's feet is necessary to provide this acceleration?

From the knowledge of Newton's Law;

we knew that ;

Force F = mass m × acceleration a

Also;

The net force  F_{net}  = frictional force \mu_k mg

so we can say that;

m×a = \mu_k mg

where;

the coefficient of static friction \mu_k is:

\mu_k = \dfrac{m*a}{m*g}

\mu_k = \dfrac{a}{g}

\mu_k = \dfrac{19 \ m/s^2}{9.81 \ m/s^2}

\mathbf{\mu_k} = 1.94

Hence; the minimum value of the coefficient of static friction between the ground and the cheetah's feet is 1.94

5 0
3 years ago
True or false? Internal motions within the object are used in creating a particle model
nikitadnepr [17]
The answer is true because it is true
5 0
3 years ago
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In a recent hockey game, one player (m=100kg) was moving at a velocity of 8 m/s when he ran into another player (m=300kg) who wa
Novay_Z [31]

Answer:

The combined velocity of players after the collision, V = 2.67 m/s

Explanation:

Given data,

The mass of the first hockey player, m₁ = 100 kg

The velocity of the first hockey player, u₁ = 8 m/s

The mass of second hockey player, m₂ = 300 kg

The velocity of the second player, u₂ = 0 m/s

According to the law of conservation of momentum,

                          m₁u₁ +m₂u₂ = MV

                             V = m₁u₁ / M                     (∵ u₂ = 0)

Substituting the given values,

                             V = 100 x 8 / 300

                                 = 2.67 m/s

Hence, the combined velocity of players after the collision, V = 2.67 m/s

8 0
3 years ago
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