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3 years ago

6

You weigh yourself at the top of a high mountain and the scale reads 728N. If your mass is 75 kg, what is the gravitational stre

ngth at your location? I'm not sure what formula to use, but once I have that I'll be good.

1 answer:

jeka943 years ago

5 0

Use. Weight = (mass)x(accel of gravity). It'll be somewhere around approx roughly about in the neighborhood of 9.706667m/sec^2 .

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A 2 kilogram object is moving horizontally with a speed of 4m/s. How much net force is required to keep the object moving at thi

zhenek [66]

IF there is no friction against the moving object (impossible in real life),
then it takes NO force to keep the object moving at a constant speed
in a straight line.

It takes force only to CHANGE the object's motion ... speed it up, slow
it down, or change its direction.

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3 years ago

A cart was pulled for a distance of 1 kilometer and the amount of work accomplished equaled 40,000 joules. With what force was t

goblinko [34]

Answer:

40 N

Explanation:

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3 years ago

Why do heavier people have a lower blood and alcohol level?

Ulleksa [173]

In general, the less you weigh the more you will be affected by a given amount of alcohol. Alcohol has a high affinity for water. Basically, one's blood alcohol concentration is a function of the total amount of alcohol in one's system divided by total body water. So for two individuals with similar body compositions and different weights, the larger individual will achieve lower alcohol concentrations than the smaller one if ingesting the same amount of alcohol.
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3 years ago

Three small balls of the same size but different masses are hung side-by-side in parallel on the strings of same length. They to

andrey2020 [161]

Answer:

m1/6 ( c )

Explanation:

since all the balls starts having the same momentum after the two collisions we will apply the principal of conservation of energy

After first collision

m1v = m1v1 + m2v2 --- ( 1 )

After second collision

m2v2 = m2v2 + m3v3 ---- ( 2 )

combining equations 1 and 2

m1v = m1v1 + m2v2 + m3v3 ----- ( 3 )

All balls moving at the same momentum ( p ) = m1v1 = m2v2 = m3v3

note ; 3p = m1v ∴ m3 = $\frac{m1v}{3v3}$ ----- ( 4 )

applying conservation of energy

3v = v1 + v2 + v3 ------- ( 5 )

also 3m1v1 = m1v = v1 = v/3 =

v2 + v3 = 8/3 v ----- ( 6 )

next eliminate V3 for equation 6 by applying conservation of energy and momentum

m1 = 2m2 ------ ( 7 )

now using p1 = p2 = m1v1 = 1/2 m1v1 hence v2 = 2v1 where v1 = 1/3 v

hence ; v2 = 2/3 v ------- ( 8 )

solving with equation 6 and 8

v3 = 2v ------ ( 9 ) ∴ v/v3 = 1/2 ---- ( 10 )

solving with equation 9 and 10

m3 = m1/3 * 1/2 = m1/6

8 0

3 years ago

A bird, accelerating from rest at a constant rate, experiences a displacement of 28 m in 11 s. what is the final velocity after

frutty [35]

Let's see what variables we've got first. Hmmm. We have:

Displacement, d = 28 m
Time taken, t = 11 s
Initial velocity, u = 0 m/s (at rest)

And now we need to find the final velocity, v. Among the 4 (or 5) equations of motions, there's no equation that will let us simply plug in the values and give an answer sigh. But fear not! We'll do it in steps.

I'm going to pick one of the motion equation to find more information:

$d = ut + \frac{1}{2} a {t}^{2}$

I know everything except for a in this one, so I I'll use this! After plugging in values, I get a = 0.4628 m/s^2.

Now I'm going to use another motion equation that has v in it because that needs to be solved!

$v = u + at$

Now I know everything except dial velocity v. Nice!

v = 0 + (0.4628)(11)

4 0

3 years ago