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Anna [14]
3 years ago
6

A particle that has a charge of 7.4 μC moves with a velocity of magnitude 3 × 105 m/s along the +x axis. It experiences no magne

tic force, although there is a magnetic field present. The maximum possible magnetic force that the charge with the given speed could experience has a magnitude of 0.520 N. Find the magnitude and direction of the magnetic field. Note that there are two possible answers for the direction of the field.
Physics
1 answer:
sweet [91]3 years ago
6 0

Answer:

Explanation:

F = qvB

Where F equal to the magnetic force on the particle.

q = charge on the particle

v = velocity of the particle

B =Magnetic field

F = 0.520N

q = 7.4 μC = 7.4×10-⁶C

v = 3×10⁵m/s

B= ?

B = F/qv

B = 0.520/(7.4×10-⁶ ×3×10⁵)

B = 0.234T.

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Sound travels through air at 343 m/s,
sasho [114]

The sound wave will have traveled 2565 m  farther in water than in air.

Answer:

Explanation:

It is known that distance covered by any object is directly proportional to the velocity of the object and the time taken to cover that distance.

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So if time is kept constant, then the distance covered by a wave can vary depending on the velocity of the wave.

As we can see in the present case, the velocity of sound wave in air is 343 m/s. So in 2.25 s, the sound wave will be able to cover the distance as shown below.

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Distance = 1483×2.25=3337 m.

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5 0
3 years ago
Please help !!!!! I’ll give brainliest !
goblinko [34]

I think A but I dont really know

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What distance does a biker travel if he rides at a constant speed or 22 m/s for 45 seconds?
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