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Triss [41]
3 years ago
7

Is density exponentially proportional to volume or inversely?

Physics
1 answer:
djverab [1.8K]3 years ago
8 0
An exponential relationship takes the form y = k(a^x), where a and b are constants. Often the value of a turns out to be Euler's number, e = 2.718281828..., because it has the special property that d/dx(e^x) = e^x. Exponential growth might model how the population of a bacterium which divides every 5 seconds increases, and exponential decay might model how the mass of a radioactive isotope sample decreases with time.

Inverse proportion takes the form

An inverse proportion takes the form y = k/x, for a constant k. This kind of relationship might model how the time taken to complete a job varies as the number of workers varies, for example.

We know the formula for density is mass over volume (d = m/v). We therefore see that when mass is considered an arbitrary constant, substitute y = d, k = m and x = v, and we have our inverse proportion.

Intuitively this makes sense. Double the volume for the same mass and the density halves. Quarter the volume for the same mass and the density quadruples.

I hope this helps you :)
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Answer:

a.) a = 0 ms⁻²

b.) a = 9.58 ms⁻²

c.) a = 7.67 ms⁻²

Explanation:

a.)

    Acceleration (a) is defined as the time rate of change of velocity

                       a = \frac{v_{2} - v_{1} } {t}  

Given data

 Final velocity = v₂ = 0 m/s

 Initial velocity = v ₁ = 0 m/s

  As the space shuttle remain at rest for the first 2 minutes i.e there is no change in velocity so,

                 a = 0 ms⁻²

b.)

     Given data

As the space shuttle start from rest, So initial velocity is zero

    Initial velocity = v₁ = 0 ms⁻¹

    Final velocity  = v₂ = 4600 ms⁻¹

     Time = t = 8 min = 480 s

By the definition of Acceleration (a)

             a = \frac{v_{2} - v_{1} } {t}  

             a = \frac{4600 - 0 } {480}

                     a = 9.58 ms⁻²

c.)

    Given data

As the space shuttle is at rest for first 2 min then start moving, So initial velocity is zero

    Initial velocity = v₁ = 0 ms⁻¹

    Final velocity  = v₂ = 4600 ms⁻¹

     Time = t = 10 min = 600 s

By the definition of Acceleration (a)

             a = \frac{v_{2} - v_{1} } {t}  

             a = \frac{4600 - 0 } {600}

                     a = 7.67 ms⁻²

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