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rusak2 [61]
3 years ago
7

A school bus moves past a parked car at a speed of 30 km/hr. Which of the following BEST describes the observation made by a pas

senger on the bus? A.The car appears to be moving 15 km/hr in the same direction as the bus.
B.The car appears to be moving 30 km/hr in the same direction as the bus.
C.The car appears to be moving 30 km/hr in the opposite direction of the bus.
D.The car appears to be moving 15 km/hr in the opposite direction of the bus.
Physics
1 answer:
ddd [48]3 years ago
8 0

Answer:

C.The car appears to be moving 30 km/hr in the opposite direction of the bus.

Explanation:

There are two reference systems involved in this situation:

- Reference system S: this is the reference system where velocities are measured with respect to the ground. In this reference system, the car is parked, so its velocity is v=0

- Reference system S': this is the reference system moving with the bus. This reference system is moving with a velocity of v_0 = +30 km/h with respect to the reference system S

Calling v' the velocity of the car in the reference system S', we have:

v=v_0 +v'

From which

v'=v-v_0 = 0-(+30 km/h)=-30 km/h

and the negative sign means that a passanger in the bus observes the car moving in the opposite direction.

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Read 2 more answers
(i) Calculate the energy, in electron volts, of a photon whose frequency is (a) 620 THz}, (b) 3.10GHz , and(c) 46.0 MHz
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The energy in electron volts of the photons that has the following frequencies is as follows:

  1. 620 THz = 2.564eV
  2. 3.10GHz = 1.28 × 10-⁵eV
  3. 46.0 MHz = 1.902 × 10-⁷eV

<h3>How to calculate energy?</h3>

The energy of a photon can be calculated using the following formula:

E = hf

Where;

  • E = energy
  • h = Planck's constant (6.626 × 10-³⁴ J/s)
  • f = frequency

First, we convert the frequencies to hertz as follows;

  • 620THz = 6.2 × 10¹⁴Hz
  • 3.10GHz = 3.1 × 10⁹Hz
  • 46.0MHz = 4.6 × 10⁷Hz

  1. E = 6.626 × 10-³⁴ × 6.2 × 10¹⁴ = 2.564eV
  2. E = 6.626 × 10-³⁴ × 3.1 × 10⁹ = 1.28 × 10-⁵eV
  3. E = 6.626 × 10-³⁴ × 4.6 × 10⁷ = 1.902 × 10-⁷eV

Learn more about energy of a photon at: brainly.com/question/2393994

#SPJ1

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