Answer:
- The emf of the generator is 6V
- The internal resistance of the generator is 1 Ω
Explanation:
Given;
terminal voltage, V = 5.7 V, when the current, I = 0.3 A
terminal voltage, V = 5.1 V, when the current, I = 0.9 A
The emf of the generator is calculated as;
E = V + Ir
where;
E is the emf of the generator
r is the internal resistance
First case:
E = 5.7 + 0.3r -------- (1)
Second case:
E = 5.1 + 0.9r -------- (2)
Since the emf E, is constant in both equations, we will have the following;
5.1 + 0.9r = 5.7 + 0.3r
collect similar terms together;
0.9r - 0.3r = 5.7 - 5.1
0.6r = 0.6
r = 0.6/0.6
r = 1 Ω
Now, determine the emf of the generator;
E = V + Ir
E = 5.1 + 0.9x1
E = 5.1 + 0.9
E = 6 V
So v=d/s so the answer is 6/3.2 so the answer is 1.87m/s

λ - wavelength, c - the speed of light, f - frequency
![f=200 \ kHz= 200 000 \ Hz \\ \\ \lambda=\frac{300 000 \ [\frac{km}{s}]}{200 000 \ [Hz]}=\frac{3}{2}=1.5 \ [km]](https://tex.z-dn.net/?f=f%3D200%20%5C%20kHz%3D%20200%20000%20%5C%20Hz%20%5C%5C%20%5C%5C%0A%5Clambda%3D%5Cfrac%7B300%20000%20%5C%20%5B%5Cfrac%7Bkm%7D%7Bs%7D%5D%7D%7B200%20000%20%5C%20%5BHz%5D%7D%3D%5Cfrac%7B3%7D%7B2%7D%3D1.5%20%5C%20%5Bkm%5D)
The wavelength of these waves is 1.5 km.
A coherent, typically large body of matter with no definitive shape
Hope this helps good luck
Answer: The Propellant fraction is 0.87.
The payload fraction is 0.04.
Δv = 8991.81 m/s
Explanation: To determine the fractions, first, calculate the total mass of the rocket:



The Propellant Fraction will be


0.87
The Payload Fraction is:


0.04
The value of Δv is calculated by the formula:
Δv = 
The exhaust velocity (
) is:

9.81*450
4414.5
is the total mass after the rocket consume all the propellant and
is the total mass before the action.
Δv = 
Δv = 
Δv = - 4414.5.ln(0.13)
Δv = 8991.81
Δv will be 8991.81 m/s.