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rusak2 [61]
4 years ago
7

A school bus moves past a parked car at a speed of 30 km/hr. Which of the following BEST describes the observation made by a pas

senger on the bus? A.The car appears to be moving 15 km/hr in the same direction as the bus.
B.The car appears to be moving 30 km/hr in the same direction as the bus.
C.The car appears to be moving 30 km/hr in the opposite direction of the bus.
D.The car appears to be moving 15 km/hr in the opposite direction of the bus.
Physics
1 answer:
ddd [48]4 years ago
8 0

Answer:

C.The car appears to be moving 30 km/hr in the opposite direction of the bus.

Explanation:

There are two reference systems involved in this situation:

- Reference system S: this is the reference system where velocities are measured with respect to the ground. In this reference system, the car is parked, so its velocity is v=0

- Reference system S': this is the reference system moving with the bus. This reference system is moving with a velocity of v_0 = +30 km/h with respect to the reference system S

Calling v' the velocity of the car in the reference system S', we have:

v=v_0 +v'

From which

v'=v-v_0 = 0-(+30 km/h)=-30 km/h

and the negative sign means that a passanger in the bus observes the car moving in the opposite direction.

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Answer:

117.83° F

Explanation:

Using Newton's Law of Cooling which can be expressed as:

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T- 70 = e^{kt+C} \\ \\ T = 70+e^{kt+C} \\ \\ T = 70 + C_1e^{kt}  --- (1)

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At the initial condition, T(0)= 350

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Hence, the differential equation becomes:

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After 4 hours, the temperature is:

T(t) = 70 + 280e^{(-0.4418)}4

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