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LekaFEV [45]
4 years ago
10

Could somebody please help this is really hard

Chemistry
1 answer:
Mars2501 [29]4 years ago
4 0

Answer:

The answers to your questions are given below

Explanation:

1. 3 Na2SO4

Molecules of Na2SO4 = 3

Na (sodium) = 3 x 2 = 6

S (sulphur) = 3 x 1 = 3

O (oxygen) = 3 x 4 = 12

2. 4 Pb(NO3)2

Molecules of Pb(NO3)2 = 2

Pb (lead) = 4 x 1 = 4

N (nitrogen) = 4 x 2 x 1 = 8

O (oxygen) = 4 x 3 x 2 = 24

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With which group would group 18 most likely bond
Mice21 [21]

Answer:

The noble gases (Group 18) are located in the right of the periodic table and were previously referred to as the "inert gases" due to the fact that their filled valence shells (octets) make them extremely nonreactivE

Explanation:

8 0
3 years ago
How many hydrogen (H) atoms are in 1 molecule of (NH4)2S ?
Alex73 [517]
Im not sure but it could be 4 (H)
3 0
3 years ago
2 NH3 + 3 CuO →3 Cu + N₂ + 3 H₂O
Tatiana [17]

40.1g of nitrogen gas is produced.

The equation given is

2 NH₃ + 3 CuO →3 Cu + N₂ + 3 H₂O

This equation is already balanced.

When 3 moles of CuO are consumed, 1 mole of nitrogen gas is produced.

We get 1 mole of nitrogen from 3 moles of copper oxide.

We need to find the number of moles of nitrogen gas produced when 4.3 moles of copper oxide are consumed.

4.3/3 x 1 = 1.433 mols

  • 1.433 mols of nitrogen gas are produced
  • The molar mass of nitrogen gas is 14+14 = 28g
  • The amount of nitrogen gas produced in grams is 28x1.433 = 40.1g

40.1g of nitrogen gas can be made when 4.3 moles of CuO are consumed.

Learn more about molarity here:

brainly.com/question/24305514

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5 0
2 years ago
Medical implants and high-quality jewelry items for body piercing are frequently known by a trade name, G23Ti, which means "surg
mrs_skeptik [129]

Answer:

Ti6Al4V1 or Ti6Al4V

Explanation:

So, from the question above we are given the following Important data or parameters or information which is going to help us in solving this question and they are;

The "surgical-grade" titanium is made up of 64.3% titanium, 24.19% aluminum and 11.42% vanadium.

This is a stoichiometry Question so in order to be able to solve this question one must have the basic knowledge of stoichiometry, it is advisable that one revise it.

So, let us delve right into the solution of this question. Recall that, the formula for Calculating the number of moles = mass/molar mass.

Hence, the number of moles of titanium,Ti = 64.3/47.87 = 3 moles.

Also, the number of moles of aluminum = 24.19/26.98 = 0.8966

For vanadium; 11.42/51 = 0.22

The next step is to divide each number of moles component by the lowest number of mole, that is;

Ti = 1.34/ 0.22 = 6; Al = 0.8966/0.22= 4 and V = 0.22/0.22 = 1.

Thus, the emperical formula is = Ti6Al4V.

7 0
3 years ago
Need answer ASAP!!!!
Keith_Richards [23]

Answer:

I am sure it is D or C. have a nice day

6 0
3 years ago
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