Question

A 70 kilogram mountaineer is standing on the summit of Mt. Everest. The distance between the mountaineer and the center of Earth is 6.39 × 106 meters. What is the magnitude of the force of gravity acting on the mountaineer? (The value of G is 6.673 × 10-11 newton meter2/kilogram2. The mass of Earth is 5.98 × 1024 kilograms.)

Answer 1

F = GMm/r² 
F = (6.673*10^-11)(5.98*10^24)(70)/(6.39*10^... 
F = 684 N (3sf)

Answer 2

Answer: The magnitude of the force of gravity acting on the mountaineer 684.09 Newtons.

Explanation:

Mass of the earth , M = $5.98\times 10^{24] kg$

Mass of the mountaineer, m = 70 kg

Distance between mountaineer and Earth,r :$6.39\times 10^{6} m$

Gravitational constant ,G = $6.673\times 10^{-11} N m^2/kg^2$

$F=G\frac{Mm}{r^2}=6.673\times 10^{-11} N m^2/kg^2\frac{5.98\times 10^{24} kg\times 70 kg}{(6.39\times 10^{6} m)^2}$

$F=684.09 N$

The magnitude of the force of gravity acting on the mountaineer 684.09 Newtons.