Given 1 gm of MCl2 fors 1.286g of AgClmolar mass of AgCl is 143.5 g 1.286g of AgCl contains 1.286/143.5 mols of AgCl =0.0089616 molseach mol of MCl2 release two Cl- ionshence number of mols MCl2 given(1gm) is 0.0089616 /2=0.0044808 mols hnce one mol of MCl2 weighs 1/0.0044808= 223.17g
Answer:
2HNO3+Ca(OH)2 ---> Ca(NO3)2+2H2O
you put the two on the H2O to make it 2H2O and A two on the HNO3 to make it 2HN03 To make it balanced
Explanation:
hope i could help every one but i'm only one person i've answered 20 (now 21) questions today my goal is to get 4 brainlyest maybe 8 if i'm lucky
During the big band only the lightest elements were formed – hydrogen<span> and </span>helium<span> along with trace amounts of </span>lithium<span> and </span>beryllium<span>.</span>
Answer:
<h2>0.11 moles</h2>
Explanation:
To find the number of moles in a substance given it's number of entities we use the formula
![n = \frac{N}{L} \\](https://tex.z-dn.net/?f=n%20%3D%20%20%5Cfrac%7BN%7D%7BL%7D%20%5C%5C)
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
![n = \frac{6.4 \times {10}^{22} }{6.02 \times {10}^{23} } \\ = 0.10631229...](https://tex.z-dn.net/?f=n%20%3D%20%20%5Cfrac%7B6.4%20%5Ctimes%20%20%7B10%7D%5E%7B22%7D%20%7D%7B6.02%20%5Ctimes%20%20%7B10%7D%5E%7B23%7D%20%7D%20%20%5C%5C%20%20%3D%200.10631229...)
We have the final answer as
<h3>0.11 moles</h3>
Hope this helps you