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malfutka [58]
3 years ago
13

Human activies that impact water cycle include

Physics
2 answers:
Tresset [83]3 years ago
8 0

Answer:

a. Use of toxic chemicals in agriculture and manufacturing run-off

Explanation:

it is the only activity listed the rest are possible impacts

KATRIN_1 [288]3 years ago
5 0

Answer:

A

Explanation:

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Velocity is about direction traveled in comparison to speed which is just distance with out direction
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A generator makes electricity from _____ A. Chemical reactions B. Friction C. Kinetic energy D. Heat
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The answer is C. Kinetic energy

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Generators don't actually create electricity. Instead, they convert mechanical or chemical energy into electrical energy. They do this by capturing the power of motion and turning it into electrical energy by forcing electrons from the external source through an electrical circuit.

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4. The nucleus of an isotope differs in the number of
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An isotope is one of two or more forms of the same chemical element. Different isotopes of an element have the same number of protons in the nucleus, giving them the same atomic number, but a different number of neutrons giving each elemental isotope a different atomic weight.

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What would happen if the sun were to become a blackhole
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A charge of -3.30 nC is placed at the origin of an xy-coordinate system, and a charge of 2.05 nC is placed on the y axis at y =
Elis [28]

Answer:

F_{3h}=39065.298\times 10^9\ N attractive toward +x axis is the net horizontal force

F_v=80062.47\times 10^9 attractive toward +y axis is the net vertical force

Explanation:

Given:

  • charge at origin, Q_0=-3.35\times 10^{-6}\ C
  • magnitude of second charge, Q_2=2.05\times 10^{-6}\ C
  • magnitude of third charge, Q_3=5\times 10^{-6}\ C
  • position of second charge, (x_2,y_2)\equiv(0,4.35)\ cm
  • position of third charge, (x_3,y_3)\equiv(3.1,3.8)\ cm

<u>Now the distance between the charge at at origin and the second charge:</u>

d_2=\sqrt{(x_2-0)^2+(y_2-0)^2}

d_2=\sqrt{(0-0)^2+(4.35-0)^2}

d_2=0.0435\ m

<u>Now the distance between the charge at at origin and the third charge:</u>

d_3=\sqrt{(x_3-0)^2+(y_3-0)^2}

d_3=\sqrt{(3.1-0)^2+(3.8-0)^2}

d_3=0.04904\ m

<u>Now the force due to second charge:</u>

F_2=\frac{1}{4\pi.\epsilon_0} \times \frac{Q_0.Q_2}{d_2^2}

F_2=9\times 10^9\times \frac{3.3\times 2.05}{0.0435^2}

F_2=32175.98\times 10^9\ N attractive towards +y

<u>Now the force due to third charge:</u>

F_3=\frac{1}{4\pi.\epsilon_0} \times \frac{Q_0.Q_3}{d_3^2}

F_3=9\times 10^9\times \frac{3.3\times 5}{0.04904^2}

F_3=61748.38\times 10^9\ N attractive

<u>Now the its horizontal component:</u>

F_{3h}=\frac{3.1}{4.9} \times 61748.38\times 10^9

F_{3h}=39065.298\times 10^9\ N attractive toward +x axis

<u>Now the its vertical component:</u>

F_{3v}=\frac{3.8}{4.9} \times 61748.38\times 10^9

F_{3v}=47886.49\times 10^9\ N upwards attractive

Now the net vertical force:

F_v=F_{3v}+F_2

F_v=47886.49\times 10^9+32175.98\times 10^9

F_v=80062.47\times 10^9

3 0
4 years ago
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