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Varvara68 [4.7K]
3 years ago
9

if an object is moving with constant speed then its distance time graph will be a straight line. a) along time axis b) along dis

tance axis c) parallel to time axis d)inclined to time axis.
Physics
1 answer:
Varvara68 [4.7K]3 years ago
5 0

Answer: I’m not sure but the time and distance will be increasing while they required the distance time so my answer is ((A))

Explanation:

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Hi there!

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\large\boxed{F_g = G\frac{m_1m_2}{r^2}}

Where:

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Plug in the given values stated in the problem:

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2 years ago
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Alekssandra [29.7K]

Answer:

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Explanation:

Doppler effect in light is actually a relativistic effect but somewhat similar to the one which happens in sound waves.

When the source is moving away from the detector, the wavelength of the light emitted from the source appears to be increased as seen by the detector, as a result the frequency decreases(we know that frequency of light= speed of light/wavelength of light. Here speed of light is constant and frequency of light is inversely proportional to its wavelength)

Due to this decrease in frequency the light emitted from the source appears more red, since red color is on low frequency side in the electromagnetic spectrum.

Similarly for the source moving towards the detector, the wavelength appears to be decreased, thereby resulting in increase in frequency and the source appears blue. The shift in frequency is known as doppler shift.

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C. Before space travel some people thought rockets would not work in space because there was no
murzikaleks [220]
Rockets can travel through space because there is no force holding or acting on them.So if the rocket travels and a certain velocity it will travel at the same velocity unless a force acts on it
5 0
3 years ago
A uniformly accelerating rocket is found to have a velocity of 11.0 m/s when its height is 4.00 m above the ground, and 1.90 s l
aleksklad [387]

Answer:

17.23 m/s²

Explanation:

Applying the equation of motion,

Δs = ut + 1/2at²..................... Equation 1

Where Δs  = change in height of the rocket, u = initial velocity of the rocket, a = acceleration of the rocket, t = time

making a the subject of the equation,

a = 2(Δs-ut)/t²..................... Equation 2

Given: Δs = (56-4) m = 52 m, u = 11.0 m/s, t = 1.90 s.

Substitute into equation 2

a = 2[52-(11×1.9)]/1.9²

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a = 62.2/3.61

a = 17.23 m/s².

Thus the acceleration = 17.23 m/s²

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