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3 years ago

Use the information from the table to answer the question.

Physics

2 answers:

Oksi-84 [34.3K]3 years ago

8 0

Answer : The money he save in one year would be, $177.009

Explanation :

First we have to calculate the cost of 1 incandescent bulbs.

Cost of 1 incandescent bulbs = Cost of single bulb × Cost of annual operating

Cost of 1 incandescent bulbs = $1.47 × $32.86

Cost of 1 incandescent bulbs = $48.3042

Now we have to calculate the cost of 10 incandescent bulbs.

Cost of 1 incandescent bulbs = $48.3042

Cost of 10 incandescent bulbs = 10 × $48.3042

Cost of 10 incandescent bulbs = $483.042

Now we have to calculate the cost of 1 CFL bulbs.

Cost of 1 CFL bulbs = Cost of single bulb × Cost of annual operating

Cost of 1 CFL bulbs = $3.99 × $7.67

Cost of 1 CFL bulbs = $30.6033

Now we have to calculate the cost of 10 CFL bulbs.

Cost of 1 CFL bulbs = $30.6033

Cost of 10 CFL bulbs = 10 × $30.6033

Cost of 10 CFL bulbs = $306.033

Money he save in one year = Cost of 10 incandescent bulbs - Cost of 10 CFL bulbs

Money he save in one year = $483.042 - $306.033

Money he save in one year = $177.009

Thus, the money he save in one year would be, $177.009

Gnesinka [82]3 years ago

4 0

Answer:

$226.70

Explanation:

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Answer:

Explanation:

Plane mirrors always form virtual images meaning although the object appears to be in the other side of the mirror the light rays actually originate in front of it. The image is inverted meaning that when you lift your right hand it shows your left hand rising. and with true orientation.

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3 years ago

A 2.1 ✕ 103-kg car starts from rest at the top of a 5.9-m-long driveway that is inclined at 19° with the horizontal. If an avera

Lina20 [59]

Answer:

3.9 m/s

Explanation:

We are given that

Mass of car,m= $2.1\times 10^3 kg$

Initial velocity,u=0

Distance,s=5.9 m

$\theta=19^{\circ}$

Average friction force,f= $4.0\times 10^3 N$

We have to find the speed of the car at the bottom of the driveway.

Net force, $F_{net}=mgsin\theta-f=2.1\times 10^3\times 9.8sin19-4.0\times 10^3$

Where $g=9.8 m/s^2$

Acceleration, $a=\frac{F_{net}}{m}=\frac{2.1\times 10^3\times 9.8sin19-4.0\times 10^3}{2.1\times 10^3}$

$v=\sqrt{2as}$

$v=\sqrt{2\times \frac{2.1\times 10^3\times 9.8sin19-4.0\times 10^3}{2.1\times 10^3}\times 5.9}$

v=3.9 m/s

7 0

3 years ago

Water pollution that elevates the temperature of the water

juin [17]

Answer:

An increase in the air temperature will cause water temperatures to increase as well. As water temperatures increase, water pollution problems will increase, and many aquatic habitats will be negatively affected.

Explanation:

Lower levels of dissolved oxygen due to the inverse relationship that exists between dissolved oxygen and temperature. As the temperature of the water increases, dissolved oxygen levels decrease.

Increases in pathogens, nutrients and invasive species.

Increases in concentrations of some pollutants such as ammonia and pentachlorophenol due to their chemical response to warmer temperatures.

Increase in algal blooms (Photo of algal blooms).

Loss of aquatic species whose survival and breeding are temperature dependent.

Change in the abundance and spatial distribution of coastal and marine species and decline in populations of some species.

Increased rates of evapotranspiration from waterbodies, resulting in shrinking of some waterbodies such as the Great Lakes.

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4 years ago

* A ball is projected horizontally from the top of

bagirrra123 [75]

Explanation:

Given

Ball is projected horizontally from a building of height $h=19.6\ m$

time taken to reach ground is given by

$\text{Cosidering vertical motion}\\\Rightarrow h=ut+0.5at^2\\\Rightarrow 19.6=0+0.5\times 9.8t^2\\\Rightarrow t^2=4\\\Rightarrow t=2\ s$

(b) Line joining the point of projection and the point where it hits the ground makes an angle of $45^{\circ}$

From the figure, it can be written

$\Rightarrow \tan 45^{\circ}=\dfrac{h}{x}\\\\\Rightarrow x=h\cdot 1\\\Rightarrow x=19.6$

Considering horizontal motion

$\Rightarrow x=u_xt\\\Rightarrow 19.6=u_x\times 4\\\Rightarrow u_x=4.9\ m/s$

$\Rightarrow v^2-u_y^2=2as\\\Rightarrow v^2-0=2\times 9.8\times 19.6\\\Rightarrow v=\sqrt{384.16}\\\Rightarrow v=19.6\ m/s$

Thus, the ball strikes with a vertical velocity of $19.6\ m/s$

6 0

3 years ago

Read 2 more answers

Need help asap

Vanyuwa [196]

I’ve done this before the answer is B

8 0

2 years ago