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3 years ago

Use the information from the table to answer the question.

Physics

2 answers:

Oksi-84 [34.3K]3 years ago

8 0

Answer : The money he save in one year would be, $177.009

Explanation :

First we have to calculate the cost of 1 incandescent bulbs.

Cost of 1 incandescent bulbs = Cost of single bulb × Cost of annual operating

Cost of 1 incandescent bulbs = $1.47 × $32.86

Cost of 1 incandescent bulbs = $48.3042

Now we have to calculate the cost of 10 incandescent bulbs.

Cost of 1 incandescent bulbs = $48.3042

Cost of 10 incandescent bulbs = 10 × $48.3042

Cost of 10 incandescent bulbs = $483.042

Now we have to calculate the cost of 1 CFL bulbs.

Cost of 1 CFL bulbs = Cost of single bulb × Cost of annual operating

Cost of 1 CFL bulbs = $3.99 × $7.67

Cost of 1 CFL bulbs = $30.6033

Now we have to calculate the cost of 10 CFL bulbs.

Cost of 1 CFL bulbs = $30.6033

Cost of 10 CFL bulbs = 10 × $30.6033

Cost of 10 CFL bulbs = $306.033

Money he save in one year = Cost of 10 incandescent bulbs - Cost of 10 CFL bulbs

Money he save in one year = $483.042 - $306.033

Money he save in one year = $177.009

Thus, the money he save in one year would be, $177.009

Gnesinka [82]3 years ago

4 0

Answer:

$226.70

Explanation:

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4 years ago

Read 2 more answers

Determine the frequency of the 2nd harmonic of a spring that has a 3rd harmonic resonance of f3=512 Hz.

Elena L [17]

Answer:

1) 341 Hz

Explanation:

When a string vibrates, it can vibrate with different frequencies, corresponding to different modes of oscillations.

The fundamental frequency is the lowest possible frequency at which the string can vibrate: this occurs when the string oscillate in one segment only.

If the string oscillates in n segments, we say that it is the n-th mode of vibration, or n-th harmonic.

The frequency of the n-th harmonic is given by

$f_n = nf_1$

where

n is the number of the harmonic

$f_1$ is the fundamental frequency

Here we have:

$f_3=512 Hz$ is the frequency of the 3rd harmonic

So the fundamental frequency is

$f_1=\frac{f_3}{3}=\frac{512}{3}=170.7 Hz$

And so, the frequency of the 2nd harmonic is:

$f_2=2f_1=2(170.7)=341.3 Hz$

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