3 years ago

Justin depends 600watts if power pushing a car 10m in 5sec how much force did he exert

Physics

1 answer:

Natasha_Volkova [10]3 years ago

5 0

Force exerted by Justin=300 N

Here power= 600 W

distance traveled=10 m

time=5 s

power is given by P= Work done/ time

600=work/5

so work= 60x5=3000J

now work done= force* distance

3000=F *10

F= 3000/10

F=300 N

You might be interested in

For a substance to change phases, the amount of Internal energy must change. Water exists in three phases: liquid, solid (ce), a

Lelechka [254]

The first one gas, liquid ,solid

8 0

2 years ago

Read 2 more answers

Which of the following is a correct comparison of a compact fluorescent lamp and incandescent light bulbs?

Alekssandra [29.7K]

The correct answer is C.

Hope I helped.

8 0

3 years ago

Read 2 more answers

A rubber ball of mass 18.5 g is dropped from a height of 1.90 m onto a floor. The velocity of the ball is reversed by the collis

kati45 [8]

Answer:

J=0.211kg.m/s

Explanation:

The impulse-momentum theorem states:

$J=\Delta p\\J=m(v_a-v-b)\\where:\\m=mass\\v_a=velocity\_after\\v_b=velocity\_before$

The velocity before the impact is given by:

$(v_b)^2=2.a.\Delta y\\v_b=\sqrt{2*(9.8m/s^2)1.90m}=6.10m/s(-\hat{j})$

For the velocity after the impact:

$(v_f)^2=(v_a)^2+2.a.\Delta y\\(0)^2=(v_a)^2+2.(-9.8m/s^s).(1.45m)\\\\v_a=\sqrt{2*9.8m/s^2*1.45m}\\v_a=5.33m/s(\hat{j})$

so:

$J=18.5*10^{-3}kg(5.33m/s(\hat{j})-6.10m/s(-\hat{j}))\\\\J=18.5*10^{-3}kg(5.33m/s(\hat{j})+6.10m/s(\hat{j}))\\\\J=0.211kg.m/s$

3 0

3 years ago

paper by itself catches fire easily whereas a piece of paper wrapped around an alluminium pipe does not.

Julli [10]

Answer:

The paper does not catch fire when wrapped around aluminium pipe because aluminium absorbs the heat, so paper does not attain its ignition temperature.

Explanation:

7 0

2 years ago

Stone needs 1350 J of energy to crack down. A bullet of 120 gm is fired on

Agata [3.3K]

There is a lot of help on the internet 350

7 0

3 years ago