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irga5000 [103]
3 years ago
15

If the time from stimulus to response from the distal stimulating electrodes is 9.5ms and the time from stimulus to response fro

m the proximal stimulating electrodes is 10.5ms and the distance between the two electrods is 55mm, what is the conduction velocity in m/s?
Physics
2 answers:
hodyreva [135]3 years ago
4 0

Answer:

The correct answer is 55m / s

Explanation:

Hello!

Let's solve this!

The formula for calculating speed is:

v = (x2-x1) / (t2-t1)

The data we have are:

x2 = 55mm * (1m / 1000mm) = 0.055

x1 = 0m

t2 = 10.5ms * (1s / 1000ms) = 0.0105s

t1 = 9.5ms * (1s / 1000ms) = 0.0095s

v = (0.055m) / (0.0105s-0.0095s) = 55m / s

The correct answer is 55m / s

S_A_V [24]3 years ago
3 0

Answer:

55m/s

Explanation:

conduction velocity (meter/second) is of a nerve is calculated by measuring the distance (millimeters) between two stimulation sites and dividing by the difference in latency (milliseconds) from the proximal.

mathematically is given as:

Conduction Velocity (meters/second) ={Distance (millimeters)}/{Proximal Latency- Distal Latency (millisecond)

C.V= (55mm)/ (10.5-9.5)ms

     =55m/s

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