Answer:
32500N
Explanation:
Data obtained from the question include:
m (mass) = 2500 kg
a (acceleration) = 13 m/s2
F (force) =?
Force is the product of mass and acceleration. It is represented mathematically as:
Force = mass x acceleration
F = m x a
With the above formula, the force with which the car strikes the barrier can be obtained as follow:
F = m x a
F = 2500 x 13
F = 32500N
Therefore, the car will strike the barrier with a force of 32500N
Explanation:
First, we need to calculate the constant force, that is, the ratio between the applied force and the rubber stretch due to the application of the force:
Now, we can know how far will an 18N force stretch the rubber. From (1):
The work done by the external force on the rubber is equal to its elastic potential energy:
Answer:
7.344 s
Explanation:
A = 0.15 x 0.3 m^2 = 0.045 m^2
N = 240
e = - 2.5 v
B1 = 0.1 T
B2 = 1.8 T
ΔB = B2 - B1 = 1.8 - 0.1 = 1.7 T
Δt = ?
e = - dФ/dt
e = - N x A x ΔB/Δt
- 2.5 = - 240 x 0.045 x 1.7 / Δt
2.5 = 18.36 / Δt
Δt = 7.344 s
Explanation:
u=0, g=9.8m/s², h=1.2m, v= ?.
from the formula => v²-u²=2gh
=> v²=2×9.8×1.2
=> v = √23.52
=> v = 4.84 m/s .
therefore, with 4.84 m/s the ball will hit the ground.
hope this helps you.
A. Through the direct contact of particles