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Bingel [31]
3 years ago
12

The sizes and shapes of the hydrogen atom orbitals was revealed through graphical analysis of the corresponding wave functions.

these wave functions also predict areas that the electrons have a zero probability of being found. these areas are known as nodes. nodes in the hydrogen atom orbitals exist either as spherical (radial) nodes or planar (angular) nodes. in the hydrogen atom, what is the total number of nodes present in a 5f orbital?
Chemistry
1 answer:
AnnZ [28]3 years ago
7 0
<span>The total number of nodes = n-1. a) In your case for the 5 d orbital 5 - 1 = 4 nodes. b) The l quantum number for a d orbital is 2. Therefore you will have 2 angular (planar) nodes. c) You have 4 nodes, 2 of which are angular. Therefore, you will also have 2 radial nodes.</span>
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n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of triprotic acid

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

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n_1=3\\M_1=?M\\V_1=250mL\\n_2=1\\M_2=0.0600M\\V_2=95.9mL

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3\times M_1\times 250=1\times 0.0600\times 95.9\\\\M_1=0.0077M

To calculate the molecular mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Molarity of solution = 0.0077 M

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Volume of solution = 250 mL

Putting values in above equation, we get:

0.0077M=\frac{0.188\times 1000}{\text{Molar mass of triprotic acid}\times 250}\\\\\text{Molar mass of triprotic acid}=97.66g/mol

Hence, the molar mass of unknown triprotic acid is 97.66 g/mol

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