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ollegr [7]
3 years ago
13

Write the balanced nuclear equation for the following. (Use the lowest possible coefficients. Omit states-of-matter in your answ

er.)
(a) electron capture by neptunium-232
Chemistry
1 answer:
olga55 [171]3 years ago
3 0

Answer:

_{93}^{232}\text{Np} + _{-1}^{0}\text{e} \longrightarrow _{92}^{232}\text{U}

Explanation:

The unbalanced nuclear equation is

_{93}^{232}\text{Np} + _{1}^{0}\text{e} \longrightarrow ?

It is convenient to replace the question by an atomic symbol, _{x}^{y}\text{Z}, where <em>x </em>= the atomic number, <em>y</em> = the mass number, and Z = the symbol of the element.

_{93}^{232}\text{Np} + _{1}^{0}\text{e} \longrightarrow _{x}^{y}\text{Z}

Then your equation becomes

_{93}^{232}\text{Np} + _{1}^{0}\text{e} \longrightarrow _{x}^{y}\text{Z}

The main point to remember in balancing nuclear equations is that the <em>sums of the superscripts and of the subscripts</em> must be the same on each side of the equation.  

Then

93 – 1 = <em>x</em>, so <em>x</em> = 92

232 + 0 = <em>y</em>, so <em>y</em> = 232

Element 92 is uranium, so the nuclear equation becomes

_{93}^{232}\text{Np} + _{-1}^{0}\text{e} \longrightarrow _{92}^{232}\text{U}

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