Answer:
0.6258 g
Explanation:
To determine the number grams of aluminum in the above reaction;
- determine the number of moles of HCl
- determine the mole ratio,
- use the mole ratio to calculate the number of moles of aluminum.
- use RFM of Aluminum to determine the grams required.
<u>Moles </u><u>of </u><u>HCl</u>
35 mL of 2.0 M HCl
2 moles of HCl is contained in 1000 mL
x moles of HCl is contained in 35 mL

We have 0.07 moles of HCl.
<u>Mole </u><u>ratio</u>
6HCl(aq) + 2Al(s) --> 2AlCl3(aq) + 3H2(g)
Hence mole ratio = 6 : 2 (HCl : Al
- but moles of HCl is 0.07, therefore the moles of Al;

Therefore we have 0.0233333 moles of aluminum.
<u>Grams of </u><u>Aluminum</u>
We use the formula;

The RFM (Relative formula mass) of aluminum is 26.982g/mol.
Substitute values into the formula;

The number of grams of aluminum required to react with HCl is 0.6258 g.
Answer:
2. 
3. 
Explanation:
Hello there!
2. In this case, we can evidence the problem by which volume and temperature are involved, so the Charles' law is applied to:

Thus, considering the temperatures in kelvins and solving for the final volume, V2, we obtain:

Therefore, we plug in the given data to obtain:

3. In this case, it is possible to realize that the 3.7 moles of neon gas are at 273 K and 1 atm according to the STP conditions; in such a way, considering the ideal gas law (PV=nRT), we can solve for the volume as shown below:

Therefore, we plug in the data to obtain:

Best regards!
There are several types of surfactants, to name two: alkylbenzene sulfonates or detergents; and lauryl sulfate or foaming agents.
Alkylbenzene sulfonates are commonly used in the production of detergent soaps, these help clean the dirt from cloths and other materials, it also produces foam.
Lauryl sulfate or foaming agents are commonly used in the production of dishwashing liquid or handwashing soap.