To develop the problem it is necessary to apply the concepts related to the ideal gas law, mass flow rate and total enthalpy.
The gas ideal law is given as,

Where,
P = Pressure
V = Volume
m = mass
R = Gas Constant
T = Temperature
Our data are given by




Note that the pressure to 38°C is 0.06626 bar
PART A) Using the ideal gas equation to calculate the mass flow,




Therfore the mass flow rate at which water condenses, then

Re-arrange to find 



PART B) Enthalpy is given by definition as,

Where,
= Enthalpy of dry air
= Enthalpy of water vapor
Replacing with our values we have that



In the conversion system 1 ton is equal to 210kJ / min


The cooling requeriment in tons of cooling is 437.2.
Answer:
c) 1.75 g/cm³
Explanation:
Given that
Radii of the A ion, r(c) = 0.137 nm
Radii of the X ion, r(a) = 0.241 nm
Atomic weight of the A ion, A(c) = 22.7 g/mol
Atomic weight of the X ion, A(a) = 91.4 g/mol
Avogadro's number, N = 6.02*10^23 per mol
Solution is attached below
Answer:
LAOD = 6669.86 N
Explanation:
Given data:
width
thickness 
crack length 2c = 0.5 mm at centre of specimen

stress intensity factor = k will be


we know that

[c =0.5/2 = 2.5*10^{-4}]
K = 0.1724 Mpa m^{1/2} for 1000 load
if
then load will be




LAOD = 6669.86 N