If in the solution, half of the added solute fails to dissolve. The solution started out supersaturated. The correct option is b.
<h3>What is supersaturation?</h3>
Supersaturation is the condition where the solutes exceed the amount that can be dissolved in a solution.
Supersaturation occurs when the solute no longer mix in the solution.
Thus, the correct option is b. The solution started out supersaturated.
Learn more about supersaturation
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Given:
T1 = 300 K
P1 = 500 kPa
P2 = 100 kPa
T2 = ?
Assume that the gas inside the container behaves ideally, we can use the ideal gas equation.
Additional assumption, volume remains constant.
PV = nRT
P/T = nR/V = constant
P1/T1 = P2/T2
500 kPa / 300 K = 100 kPa / T2
T2 = 60 K
Its D for plato.
by other people who asked
Answer:
G : pent-2-ene
H : H2o
I : pent-1-ene
Explanation:
The OH would combine with H from H-O4SH
Then the O attached to the carbon would get detached taking the electrons with it, leaving carbon an positively charged.
The OH now combined with H-O4SH would take the H away from the acid forming H2O and (O4SH)-
The negative ion of (O4SH)- would then take the H from positively charged C forming the sulphuric acid back. It does not take the electrons with it*
Which is why the carbon can then form a double bond with the excess electron (2). the major product would be pent-2-ene and minor would be pent-1-ene.
This is because pent-2-ene is more stable than pent-1-ene. (Due to secondary carbon and primary carbon factor)
This is the whole backstage story though.