Answer:
cornea, pupil, lens, vitreous humor
Answer:
I think it would be:
NaCO3 (s)-->Na2O (s) + CO2 (g)
It is when you separate two substances using electricity of its molten state like aluminium oxide separates to aluminium and oxygen
Answer:
10 L
Explanation:
The only variables are pressure and volume, so we can use Boyle's Law:
p1V1 = p2V2
Data:
p1 = 125 atm; V1 = 4.0 L
p2 = 50 atm; V2 = ?
Calculation:
125 × 4.0 = 50V2
500 = 50 V2
V2 = 500/50 = 10 L
The new volume will be 10 L.
Phosphorus can be prepared from calcium phosphate by the following reaction:

Phosphorite is a mineral that contains
plus other non-phosphorus-containing compounds. What is the maximum amount of
that can be produced from 2.3 kg of phosphorite if the phorphorite sample is 75%
by mass? Assume an excess of the other reactants.
Answer: Thus the maximum amount of
that can be produced is 0.345 kg
Explanation:
Given mass of phosphorite
= 2.3 kg
As given percentage of phosphorite
is = 



According to stoichiometry:
2 moles of phosphorite gives = 1 mole of 
Thus 5.56 moles of phosphorite give=
of 
Mass of 
Thus the maximum amount of
that can be produced is 0.345 kg