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4 years ago

There are _____ periods included in the periodic table.

Physics

2 answers:

zhannawk [14.2K]4 years ago

6 0

Answer:

There are 7 periods in the periodic table. Remember periods are the rows.

Brainliest always helps!!!

torisob [31]4 years ago

4 0

Answer: 7 Periods

Explanation:There are 7 periods in the periodic table. They are arranged in rows(Horizontal) and columns(Vertical).

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Question 1 of 10

Hoochie [10]

Answer:

The neutron is a subatomic particle, symbol

, with no electric charge and a mass slightly greater than that of a proton. Protons and neutrons constitute the nuclei of atoms. Since protons and neutrons behave similarly within the nucleus, and each has a mass of approximately one atomic mass unit, they are both referred to as nucleons.[6] Their properties and interactions are described by nuclear physics.

Explanation:

pls mark me as BRAINLIEST

5 0

3 years ago

A ball is thrown horizontally from the top of a building and strikes the sidewalk after 2.8 s. How tall is the building? Neglect

Brut [27]

Answer:

h = 38.41 m

Explanation:

Given that,

A ball is thrown horizontally from the top of a building and strikes the sidewalk after 2.8 s.

We need to find the height of the building. Let it is h.

Initial speed of the ball, u = 0

Using second equation of motion to find h as follows :

$h=ut+\dfrac{1}{2}at^2\\\\\text{Put u = 0 and a = g}\\\\h=\dfrac{1}{2}gt^2\\\\=\dfrac{1}{2}\times 9.8\times 2.8^2\\\\=38.41\ m$

So, the building is 38.41 m tall.

3 0

3 years ago

Helpp me please i need it rn

Mandarinka [93]

Answer:

figure c

Explanation:

a neutral body has the same number of charge that's the negatives and positive charges are equal.

6 0

3 years ago

Read 2 more answers

Q/C A man claims that he can hold onto a 12.0 -kg child in a head-on collision as long as he has his seat belt on. Consider this

Nimfa-mama [501]

Average force $F_{avg}$ =3216N

How this is calculated?

Given:

$m=12kg$

$v_i=60mi/h=26.8m/s\\v_f=0\\t=0.10s$

We know that,

I=Δp(according to impulse momentum theorem)

I= $F_{avg}$ Δt

So, $F_{avg}$ Δt=Δp

$=p_f-p_i\\=mv_f-mv_i\\$

$F_{avg}=\frac{mv_i}{delta t} \\\\ =\frac{12*26.8}{0.1} \\$ =3216N

What is the average force?

The average force is the force exerted by some object moving at some defined rate of speed i.e. velocity for a defined period of time.
The word average here is used to indicate that this is not an instantaneous or precisely measured velocity.

To know more about average force, refer:

brainly.com/question/18652903

#SPJ4

8 0

1 year ago

Answer number 19 pls

kogti [31]

Answer:

1. Net force = 90 N

2. Acceleration = 9 m/s²

Explanation:

From the question given above, the following data were obtained:

Mass (m) of bag = 10 Kg

Force applied 1 (Fₐ₁) = 45 N

Force applied 2 (Fₐ₂) = 60 N

Force of friction (Fբ) = 15 N

Net force (Fₙ) =?

Acceleration (a) =?

1. Determination of the net force acting on the bag.

We'll begin by calculating the total force applied on the bag.

Force applied 1 (Fₐ₁) = 45 N

Force applied 2 (Fₐ₂) = 60 N

Total force applied = Fₐ₁ + Fₐ₂

Total force applied = 45 + 60

Total force applied = 105 N

Finally, we shall determine the net force acting on the bag. This is illustrated below:

Total force applied = 105 N

Force of friction (Fբ) = 15 N

Net force (Fₙ) =?

Net force (Fₙ) = Total force applied – Force of friction (Fբ)

Net force (Fₙ) = 105 – 15

Net force (Fₙ) = 90 N to the right

2. Determination of the acceleration of the bag.

Mass (m) of bag = 10 Kg

Net force (Fₙ) = 90 N

Acceleration (a) =?

Force (F) = mass (m) × acceleration (a)

90 = 10 × a

Divide both side by 10

a = 90 / 10

a = 9 m/s²

Thus, the acceleration of the bag is 9 m/s² to the right.

3 0

3 years ago