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Anastaziya [24]
3 years ago
8

A possum is trying to cross the street. Its velocity v as a function of time t is given in the graph below

Physics
1 answer:
AlladinOne [14]3 years ago
4 0

Answer:

-10

Explanation:

The rectangular area is the base bbb times height hhh.

\begin{aligned}\Delta x&= A \\\\ &=(2\,\text s)\left (-5\,\dfrac{\text m}{\text s}\right ) \\\\ &= -10\,\text m\end{aligned}

Δx

​

 

=A

=(2s)(−5

s

m

​

)

=−10m

​

The possum displaces 10\,\text m10m10, start text, m, end text to the left.

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PLEASE ANSWER, I NEED HELP
Scorpion4ik [409]

1) The gravitational force between Ellen and the moon is 1.56\cdot 10^{-3} N

2) The two forces are equal, while the acceleration of the bus is smaller than the acceleration of the bicycle.

Explanation:

1)

The magnitude of the gravitational force between two objects is given by

F=G\frac{m_1 m_2}{r^2}

where

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

m_1, m_2 are the masses of the two objects

r is the separation between them

In this problem, we have:

m_1 = 47 kg is the mass of Ellen

m_2 = 7.35\cdot 10^{22} kg is the mass of the moon

r=3.84\cdot 10^8 m is the distance between Ellen and the moon

Substituting, we find the gravitational force between Ellen and the moon:

F=(6.67\cdot 10^{-11})\frac{(47)(7.35\cdot 10^{22})}{(3.84\cdot 10^8)^2}=1.56\cdot 10^{-3} N

2)

We can analyze the forces acting in the collision between the bus and the bicycle by using Newton's third law of motion, which states that:

"When an object A exerts a force (called action) on an object B, then object B exerts an equal and opposite force (called reaction) on object A"

Applied to our problem, this means that the force exerted by the bus on the bicycle during the collision (action force) is equal (and opposite) to the force exerted by the bicycle on the bus (reaction force).

Now let's analyze the accelerations of the two vehicles. We can find the acceleration of each vehicle by using Newton's second law:

a=\frac{F}{m}

where

a is the acceleration

F is the force exerted on the vehicle

m is the mass of the vehicle

As we said previously, the force F exerted on each of the two vehicles: so, the acceleration only depends on the mass. In particular, the acceleration is inversely proportional to the mass: therefore, the larger the mass of the vehicle, the smaller the acceleration. This means that the acceleration of the bus is smaller than the acceleration of the bicycle.

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

And about Newton's third law:

brainly.com/question/11411375

#LearnwithBrainly

6 0
3 years ago
What is the effect of load resistor on ripple factor
Zolol [24]
<span>ripple factor can be reduced by increasing the value of the load resistor (which means reducing the load of the circuit)</span>
7 0
3 years ago
A machine runs for 50 seconds with a steady power output of 100 watts. How many joules of work does the
liberstina [14]

Answer:

The answer to your question is when time = 50 s, work = 5000 J

                                                    when time = 90 s, work = 9000 J

Explanation:

Data

time = 50 s or 90 s

Power = 100 watts

Power is defined as the rate of work done per unit of time.

           Power = Work / time

-Solve for Work

           Work = Power x time

-Substitution

           Work = 100 x 50

-Result

           Work = 5000

2.-When time = 90 s

           Work = 100 x 90

-Result

          Work = 9000 watts

6 0
2 years ago
a baby carriage is sitting at the top of a hill that is 21 m high. The carriage with the baby weighs 12 Kg. how much energy does
Tcecarenko [31]

Answer:

The carriage has the energy, W = 2469.6 J

Explanation:

Given data,

The height of the hill, h = 21 m

The carriage with the baby weighs, m = 12 kg

The energy possessed by the body due to its position is the potential energy,

                                      <em>W = P.E = mgh joules</em>

Substituting the values,

                                       W = 12 x 9.8 x 21

                                            = 2469.6 J

Hence, the carriage has the energy, W = 2469.6 J

8 0
3 years ago
suppose you increase your walking speed from 4 m/s to 12 m/s in a period of 1 second what is your acceleration
KiRa [710]

a   = 12 ms⁻¹ - 4ms⁻¹ / 1 s

a  =    8 ms⁻²

7 0
3 years ago
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