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VLD [36.1K]
3 years ago
7

A charged particle (Q = 6 C, m = 0.02 kg) moves at a speed of 70 m/s perpendicular to the direction of a uniform magnetic field

of 0.03 T. What is the magnitude of the force exerted by the magnetic field on the charge?
Physics
1 answer:
san4es73 [151]3 years ago
5 0

Answer:

Explanation:

When a charged particle moves in a magnetic field , a force acts on it perpendicular to its velocity.

Force = Bqv , B is magnetic field , q is charge of the particle and v is velocity

= .03 x 6 x 70

= 12.6 N

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Question 1  

In order to do work, the force vector must be

in the same direction as the displacement vector and the motion.

Question 2  

In which of the following cases is work being done on an object?

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Question 3  

Which situation is an example of NOT doing work?

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Question 4  

Work is measured in

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Question 5  

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When more work was done, the couch was moved further.

Question 6  

A weight lifter raises a 1600 N barbell to a height of 2.0 meters. How much work was done? W = Fd

3200 Joules

Question 7  

You and a friend (Alex) are at a a tree-top adventure park .. . . part of the course requires you to climb up a rope. You both climb the same rope in the same amount of time. However, the tension in the rope is greater

when Alex climbs. Who did the most work?

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Question 8  

Doing work at a faster rate creates power.

more

Question 9  

In one challenge on the Titan Games, competitors have to lift 200 pounds up a long ramp. Angel is able to move the weight in 42 seconds. Anthony gets it done in only 38 seconds. Which statement is true?

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Question 10  

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82 Watts

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Your family is moving to a new apartment. While lifting a box 83 Joules of work is done to put the box on a truck, you exert an upward force of 75 N for 3 s. How much power is required to do this? (Hint: You only need two of the 3 numbers given!) Power = Work / time

27.7 Watts

<em>*100% CORRECT ANSWERS</em>

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