A charged particle (Q = 6 C, m = 0.02 kg) moves at a speed of 70 m/s perpendicular to the direction of a uniform magnetic field

Question

3 years ago

7

of 0.03 T. What is the magnitude of the force exerted by the magnetic field on the charge?

1 answer:

san4es73 [151] · Answer 1 · 2021-11-21T23:13:45+03:00

5 0

Answer:

Explanation:

When a charged particle moves in a magnetic field , a force acts on it perpendicular to its velocity.

Force = Bqv , B is magnetic field , q is charge of the particle and v is velocity

= .03 x 6 x 70

= 12.6 N