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Komok [63]
3 years ago
13

If the first energy level can hold 2 electrons, the second holds 8, and the third can hold 8, what if the atomic number is bigge

r than 18? Where do the other electrons go?
Chemistry
1 answer:
sergejj [24]3 years ago
4 0
You're wrong because the third energy level can contain 18 <span>electrons. And the 4th have up to 32 elections.

The pattern go by 2-8-18-32</span>
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Read 2 more answers
You have a 150mL sample of an aqueous solution at 25C. It contains 15.2mg of an unknown nonelectrolyte compound. If the solution
Serga [27]

The molar mass of the compound:

If the solution has an osmotic pressure of 8.44 torr, then the molar mass of the unknown non-electrolyte is 223.14 g.

What is osmosis?

  • Osmosis is defined as the flow of solvent molecules through semi-permeable membrane.
  • Osmotic pressure is the pressure applied to stop the flow of solvent molecules.
  • It is a colligative property that means osmotic pressure depends on the number of solute particles .

Therefore,

πV=inRT  ( for electrolytes)

Where,   π= Osmotic pressure

i = Van 't Hoff factor

n= moles

R= Gaseous constant = 62.363577 L torr mol^{-1}K^{-1}

T= Temperature

V= Volume of solution

Given:

T= 298K

V= 150 mL= 0.150 L

Given mass of unknown electrolyte= 15.2 mg = 15.2 x  10^{-3} g

Osmotic pressure= 8.44 torr

Molar mass= ?

For non-electrolytes:

πV = n RT

πV=\frac{m}{M}RT

Calculations:

Putting the given values in the formula:

8.44 x 0.150 =15.2 x 10^{-3}/ M x 62.36 x 298

1.266 = 282.5/M

M = 282.5/1.266

M = 223.14 g

Therefore,

The molar mass of the unknown non-electrolyte is 223.14g.

Learn more about Osmotic pressure here,

brainly.com/question/13680877

#SPJ4

7 0
2 years ago
D = 24 g/ml<br> v = 1200 ml<br> m = ?
8_murik_8 [283]

Answer:

<h2>28,800 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question we have

mass = 24 × 1200

We have the final answer as

<h3>28,800 g</h3>

Hope this helps you

5 0
3 years ago
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