1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Komok [63]
3 years ago
13

If the first energy level can hold 2 electrons, the second holds 8, and the third can hold 8, what if the atomic number is bigge

r than 18? Where do the other electrons go?
Chemistry
1 answer:
sergejj [24]3 years ago
4 0
You're wrong because the third energy level can contain 18 <span>electrons. And the 4th have up to 32 elections.

The pattern go by 2-8-18-32</span>
You might be interested in
a scientists finds an organism that cannot move. it has many cells, produces spores, and gets food from its environment. in whic
lord [1]

The correct answer is : The Organism belongs in Kingdom Fungi


The explanation:


1) because Fungi can be multicellular


2) most of them cannot move.


3) They can get food by releasing digestive juices into their environment.

3 0
3 years ago
When 61.6 g of alanine (C3H7NO2) are dissolved in 1150. g of a certain mystery liquid X, the freezing point of the solution is 2
MrRissso [65]

Answer:

Explanation:

From the given information:

TO start with the molarity of the solution:

= \dfrac{61.6 \ g \times \dfrac{1 \ mol \ C_3H_7 NO_3}{89.1 \ g} }{1150 \ g \times \dfrac{1 \ kg}{1000 \g }}

= 0.601 mol/kg

= 0.601 m

At the freezing point, the depression of the solution is \Delta \ T_f = T_{solvent}- T_{solution}

\Delta \ T_f = 2.9 ^0 \ C

Using the depression in freezing point, the molar depression constant of the solvent K_f = \dfrac{\Delta T_f}{m}

K_f = \dfrac{2.9 ^0 \ C}{0.601 \ m}

K_f = 4.82 ^0 C / m}

The freezing point of the solution \Delta T_f = T_{solvent} - T_{solution}

\Delta T_f = 7.3^ 0 \ C

The molality of the solution is:

= \dfrac{61.6 \ g \times \dfrac{1 \ mol \ NH_4Cl}{53.5 \ g} }{1150 \ g \times \dfrac{1 \ kg}{1000 \g }}

Molar depression constant of solvent X, K_f = 4.82 ^0 \ C/m

Hence, using the elevation in boiling point;

the Vant'Hoff factor i = \dfrac{\Delta T_f}{k_f \times m}

i = \dfrac{7.3 \ ^0 \ C}{4.82 ^0 \ C/m \times 1.00 \ m}

\mathbf {i = 1.51 }

3 0
2 years ago
What is the freezing point of a solution of 0.5 mol of LiBr in 500 mL of water? (Kf = 1.86°C/m) –1.86°C –7.44°C –5.58°C –3.72°C
tresset_1 [31]

Answer:

  • Last choice: <em><u>- 3.72°C</u></em>

Explanation:

The freezing point depression in a solvent is a colligative property: it depends on the number of solute particles.

The equation to predict the freezing point depression in a solvent is:

  • ΔTf = Kf × m × i

Where,

  • ΔTf is the freezing point depression of the solvent,
  • m is the molality,
  • Kf is the cryoscopic molal constant of the solvent, and i is the Van'f Hoff factor, which is the number of ions produced by each unit formula of the ionic compound.

The calcualtions are in the attached pdf file. Please, open it by clicking on the image of the file.

Download pdf
6 0
2 years ago
Mass is measured in= a. Liters b. centimeters c. newtons d. kilograms
ale4655 [162]
Mass is measured in kilograms.
5 0
2 years ago
How many moles of aluminum oxide (Al2O3) can be produced from 12.8 moles of oxygen gas (02)
zhannawk [14.2K]

Answer:

Theoretical Yield

Percent yield

Example stoichiometry problem

How much oxygen can be prepared from 12.25 g KClO3 . (Use molar mass KClO3 = 122.5 g.)

Most stoichiometry problems can be solved using the following steps.

Step 1.

Write and balance the equation for the decomposition of KClO3 with heat (∆). 2KClO3 + ∆ → 2KCl + 3O2

Step 2.

Convert what you have (in this case g KClO3) to moles.

# moles = grams/molar mass = 12.25 g /122.5 = 0.100 mole KClO3.

Step 3.

Using the coefficients in the balanced equation, convert moles of what you have (moles KClO3) to moles of what you want (in this case moles oxygen).

0.100 mol KClO3 x (3 moles O2/2 moles KClO3) = 0.100 x (3/2) = 0.150 mole O2.

Step 4.

Convert moles from step 3 to grams.

moles x molar mass = grams

0.150 mole O2 x (32.0 g O2/mole O2) = 4.80 g O2 produced from 12.25 g KClO3. This is the theoretical yield. If the ACTUAL yield is 4.20 grams, calculate percent yield. Percent yield = (actual yield/theoretical yield) x 100 = (4.20/4.80) x 100 = 87.5% yield

NOTE: In step 1, moles can be obtained other ways; in step 4 moles can be converted to other units.

a. For solutions, M x L = moles (or mL x M = millimoles).

b. For gases, L/22.4 = moles

4 0
3 years ago
Other questions:
  • A _________________ is developed through the scientific method, and it can be modified or improved upon. It may be represented b
    10·2 answers
  • A projectile is fired with speed v0 at an angle theta from the horizontal from the horizontal as shown in the figure.
    13·1 answer
  • Which redox equation is correctly balanced?
    15·1 answer
  • How many moles are there in 140.2 g of Ca
    10·2 answers
  • How many moles of water are produced if 5.43 mol PbO2 are consumed?<br><br> ANSWER: 10.9
    9·2 answers
  • calculate the frequency of the light emitted by a hydrogen atom during a transition of its electron from the n = 3 to n = 1 ener
    10·1 answer
  • Given the amount of camphor (200mg) we are using in this experiment, please determine how many mg of sodium borohydride to use i
    11·1 answer
  • Do all mutations affect the STRUCTURE of proteins ? Do all mutations affect the FUNCTIONS of proteins??
    7·1 answer
  • Connect as many terms that you can think of. Each term should be related to
    7·2 answers
  • Can you write the answer for lot of points ​
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!