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The range of force exerted at the end of the rope is 285.7 N to 1,000 N.
<h3>Net horizontal force of the cylinder</h3>
The net horizontal force of the cylinder when it is at equilibrium position is determined by applying Newton's second law of motion.
∑F = 0
F - μFn = 0
F - 0.2(5,000) = 0
F - 1,000 = 0
F = 1,000 N
The strength of the applied force increases as the number of turns of the rope increases.
minimum force = total force/number of turns of rope
minimum force = 1,000/3.5
minimum force = 285.7 N
Thus, the range of force exerted at the end of the rope is 285.7 N to 1,000 N.
Learn more about Newton's second law of motion here: brainly.com/question/3999427
Answer:
coordination
Explanation:
I know because I just took the test and got the answer right.
Explanation:
We need to calculate the time it had travelled first:
9:00 to 12:00 = 3 hours.
12:00 to 2:00 = 2 hours
Total travel time = 5 hours.
The formula for speed is distance ÷ time (Hence, the unit for speed is m/s, kph, mph, etc.)
= 629km ÷ 5 hours
= 125.8 km/hour ~ 125.8kph